\(\frac{3}{7}\left(7x+\frac{2}{3}\right)-2\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}-\frac{5}{7}+6x=3\)
\(\Leftrightarrow9x=\frac{24}{7}\)
\(\Leftrightarrow x=\frac{8}{21}\)
\(\frac{3}{7}.\left(7x+\frac{2}{3}\right)-2.\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)
\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)
\(\Leftrightarrow\frac{65}{7}.x=3+\frac{5}{7}\)
\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)
\(\Leftrightarrow x=\frac{26}{7}:\frac{65}{7}\)
\(\Leftrightarrow x=\frac{2}{5}\)
3/7.(7x+2/3)-2.(5/14-3x)=15/5
\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)
\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)
\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)\(\Leftrightarrow x=\frac{2}{5}\)
Vậy x =\(\frac{2}{5}\)
\(\frac{3}{7}.\left(7x+\frac{2}{3}\right)-2\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
<=> \(\left(3x+\frac{2}{7}\right)-\left(\frac{5}{7}-6x\right)=\frac{15}{5}\)
<=> \(3x+\frac{2}{7}-\frac{5}{7}+6x=\frac{15}{5}\)
<=> \(9x-\frac{3}{7}=3\)
<=> \(9x=\frac{24}{7}\)
<=> \(x=\frac{24}{7}.\frac{1}{9}=\frac{8}{21}\)