Giải giúp mik với ạ mik đang cần gấp
giải giúp ạ mik với ạ . em đang cần gấp.
Câu 5:
\(\dfrac{13}{6}+x=-2,4\)
\(\Rightarrow\dfrac{13}{6}+x=-\dfrac{12}{5}\)
\(\Rightarrow x=-\dfrac{12}{5}-\dfrac{13}{6}\)
\(\Rightarrow x=-\dfrac{137}{30}\)
Câu 6:
\(3,7-x=\dfrac{7}{10}\)
\(\Rightarrow\dfrac{37}{10}-x=\dfrac{7}{10}\)
\(\Rightarrow x=\dfrac{37}{10}-\dfrac{7}{10}\)
\(\Rightarrow x=3\)
Câu 7:
\(\dfrac{3}{7}+x=\dfrac{2}{14}\)
\(\Rightarrow\dfrac{3}{7}+x=\dfrac{1}{7}\)
\(\Rightarrow x=\dfrac{1}{7}-\dfrac{3}{7}\)
\(\Rightarrow x=-\dfrac{2}{7}\)
Câu 8:
\(\dfrac{3}{7}\cdot y=\dfrac{-2}{5}\)
\(\Rightarrow y=\dfrac{-2}{5}:\dfrac{3}{7}\)
\(\Rightarrow y=\dfrac{-2}{5}\cdot\dfrac{7}{3}\)
\(\Rightarrow y=-\dfrac{14}{15}\)
Mik đang cần gấp giúp mik giải vs ạ! Mik cảm ơn ạ!
1 are
2 am
3 is
4 are
5 are
6 are
7 is
8 is
9 is
10 are
IV
1 is writing
2 are losing
3 is having
4 is staying
5 am not lying
6 is always using
7 are having
8 Are you playing
9 are not touching
10 Is - listening
11 Is- winning
12 am not staying
13 is not working
14 is not reading
15 isn't raining
16 am not listening
17 Are they making
18 Are you doing
19 Is - sitting
20 is - doing
21 are-putting
22 are-wearing
23 is-studying
2, am
3, is
4,are
5,are
6,are
7,is
8,is
9,is
10,are
IV
1,2,7 OK
3,is having
4,has stayed
5,am not lying
6,always uses
8,Are-playing
9,not to touch
10,Is-listening
11,Are-winning
12,am not staying
13,isn't working
14,isn't reading
15,isn't raining
16,am not listening
17,Are-making
18,Are-doing
19,Is-sitting
20,is-doing
21,do-putting
22,do-wear
23,is-studying
giải giúp mik vs ạ mik đang cần gấp.
giải giúp mik vs ạ mik đang cần gấp!!!
giải giúp mik vs mik đang cần gấp ạ
1. a) 6² : 4 . 3 + 2 . 5²
= 36 : 4 . 3 + 2 . 25
= 9 . 3 + 50
= 27 + 50
= 77
b) 5 . 4² - 32 : 4²
= 5 . 16 - 32 : 16
= 80 - 2
= 78
c) 80 - (4 . 5² - 3 .2³)
= 80 - (4 . 25 - 3 . 8)
= 80 - (100 - 24)
= 80 - 76
= 4
d) 2448 : [119 - (23 - 6)]
= 2448 : (119 - 17)
= 2448 : 102
= 24
e) 23 . 85 + 15 . 23 + 170
= 23 . (85 + 15) + 170
= 23 . 100 + 170
= 2300 + 170
= 2470
f) 3³ . 2 - 5 . 2023⁰ + 36 : 3²
= 27 . 2 - 5 . 1 + 36 : 9
= 54 - 5 + 4
= 53
2. a) 123 - 5.(x + 4) = 38
5.(x + 4) = 123 - 38
5.(x + 4) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
b) (3.x - 2⁴) . 7³ = 2 . 7⁴
3x - 16 = 2 . 7⁴ : 7³
3x - 16 = 2 . 7
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
c) (2600 + 6400) - 3.x = 1200
9000 - 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 7800 : 3
x = 2600
d) [(6.x - 72) : 2 - 84] . 28 = 5628
(6x - 72) : 2 - 84 = 5628 : 28
(6x - 72) : 2 - 84 = 201
(6x - 72) : 2 = 201 + 84
(6x - 72) : 2 = 285
6x - 72 = 285 . 2
6x - 72 = 570
6x = 570 + 72
6x = 642
x = 642 : 6
x = 107
e) 70 - 5(x - 3) = 45
5(x - 3) = 70 - 45
5(x - 3) = 25
x - 3 = 25 : 5
x - 3 = 5
x = 5 + 3
x = 8
f) 10 + 2.x = 4⁷ : 4⁵
10 + 2x = 4²
10 + 2x = 16
2x = 16 - 10
2x = 6
x = 6 : 2
x = 3
g) 2.x - 138 = 2³.2²
2x - 138 = 2⁵
2x - 138 = 32
2x = 32 + 138
2x = 170
x = 170 : 2
x = 85
h) 231 - (x - 6) = 1339 : 13
231 - (x - 6) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
1.Tính:
a) \(6^2:4.3+2.5^2\)
\(=36:4.3+2.25\)
\(=9.3+50\)
\(=27+50\)
\(=77\)
b) \(5.4^2-32:4^2\)
\(=5.16-32:16\)
\(=80-2\)
\(=78\)
c) \(80-\left(4.5^2-3.2^3\right)\)
\(=80-\left(4.25-3.8\right)\)
\(=80-\left(100-24\right)\)
\(=80-76\)
\(=4\)
d) \(2448:\left[119-\left(23-6\right)\right]\)
\(=2448:\left[119-17\right]\)
\(=2448:102\)
\(=24\)
e) \(23.85+15.23+170\)
\(=23\left(85+15\right)+170\)
\(=23.100+170\)
\(=2300+170\)
\(=2470\)
f) \(3^3.2-5.2023^0+36:3^2\)
\(=27.2-5.1+36:9\)
\(=54-5+4\)
\(=53\)
2. Tìm x biết:
a) \(123-5.\left(x+4\right)=38\)
\(=>5.\left(x+4\right)=123-38\)
\(=>5.\left(x+4\right)=85\)
\(=>x+4=85:5\)
\(=>x+4=17\)
\(=>x=17-4\)
\(=>x=13\)
b) \(\left(3.x-2^4\right).7^3=2.7^4\)
\(=>3.x-2^4=2.7^4:7^3\)
\(=>3.x-2^4=2.7\)
\(=>3.x-16=14\)
\(=>3.x=14+16\)
\(=>3.x=30\)
\(=>x=30:3\)
\(=>x=10\)
c) \(\left(2600+6400\right)-3.x=1200\)
\(=>9000-3.x=1200\)
\(=>3.x=9000-1200\)
\(=>3.x=7800\)
\(=>x=7800:3\)
\(=>x=2600\)
d) \(\left[\left(6.x-72\right):2-84\right].28=5628\)
\(=>\left(6.x-72\right):2-84=5628:28\)
\(=>\left(6.x-72\right):2-84=201\)
\(=>\left(6.x-72\right):2=201+84\)
\(=>\left(6.x-72\right):2=285\)
\(=>6.x-72=285\times2\)
\(=>6.x-72=570\)
\(=>6.x=570+72\)
\(=>6.x=642\)
\(=>x=642:6\)
\(=>x=107\)
e) \(70-5.\left(x-3\right)=45\)
\(=>5.\left(x-3\right)=70-45\)
\(=>5.\left(x-3\right)=25\)
\(=>x-3=25:5\)
\(=>x-3=5\)
\(=>x=5+3\)
\(=>x=8\)
f) \(10+2.x=4^7:4^5\)
\(=>10+2.x=4^2\)
\(=>10+2.x=16\)
\(=>2.x=16-10\)
\(=>2.x=6\)
\(=>x=6:2\)
\(=>x=3\)
g) \(2.x-138=2^3.3^2\)
\(=>2.x-138=8.9\)
\(=>2.x-138=72\)
\(=>2.x=72+138\)
\(=>2.x=210\)
\(=>x=210:2\)
\(=>x=105\)
h) \(231-\left(x-6\right)=1339:13\)
\(=>231-\left(x-6\right)=103\)
\(=>x-6=231-103\)
\(=>x-6=128\)
\(=>x=128+6\)
\(=>x=134\)
Chúc bạn học tốt
M.n giải giúp mik vài cuối đc kh ạ mik đang cần gấp ạ
Bài 4
uses crt;
var a,b: integer;
c,s,d:real;
begin
clrscr;
readln(a,b);
if (a>0) and (b>0) then
begin
c:=sqrt(a*a+b*b);
d:=(a+b+c)/2;
s:=sqrt(d*(d-a)*(d-b)*(d-c));
writeln(c:4:2,' ',s:4:2);
end
else writeln('nhap lai');
readln
end.
Bài 5
uses crt;
var r: integer;
s,t: real;
begin
clrscr;
readln(r);
s:=r*r*3.14;
t:=2*3.14*r;
writeln(s:4:2,' ',t:4:2);
readln
end.
bài 6
uses crt;
var a,b,x: INTEGER;
s,v,t: real;
begin
clrscr;
readln(a,b,x);
s:=a*b;
v:=(x*(b-x))/2;
t:=s/2;
writeln(s:4:1);
writeln(v:4:1);
write(t:4:1);
readln
end.
Giải bài tập giúp mik vs ạ 🥺... mik đang cần gấp lắm ạ...
Câu 3:
a: Ta có: \(2x\left(3x-1\right)-\left(x-3\right)\left(6x+2\right)\)
\(=6x^2-2x-6x^2-2x+18x+6\)
=14x+6
b: Ta có: \(2x\left(x+7\right)-3x\left(x+1\right)\)
\(=2x^2+14x-3x^2-3x\)
\(=-x^2+11x\)
Câu 2:
a: Ta có: \(\left(-8x^5+12x^3-16x^2\right):4x^2\)
\(=-8x^5:4x^2+12x^3:4x^2-16x^2:4x^2\)
\(=-2x^3+3x-4\)
b: Ta có: \(\left(12x^3y^3-18x^2y+9xy^2\right):6xy\)
\(=12x^3y^3:6xy-18x^2y:6xy+9xy^2:6xy\)
\(=2x^2y^2-3x+\dfrac{3}{2}y\)
c: Ta có: \(\dfrac{x^3-11x^2+27x-9}{x-3}\)
\(=\dfrac{x^3-3x^2-8x^2+24x+3x-9}{x-3}\)
\(=x^2-8x+3\)
d: Ta có: \(\dfrac{6x^4-13x^3+7x^2-x-5}{3x+1}\)
\(=\dfrac{6x^4+2x^3-15x^3-5x^2+12x^2+4x-5x-\dfrac{5}{3}-\dfrac{10}{3}}{3x+1}\)
\(=2x^3-5x^2+4x-\dfrac{5}{3}-\dfrac{\dfrac{10}{3}}{3x+1}\)
Giải hộ mik ạ. Mấy bài mik chụp í. Làm nhanh giúp ạ mik đang cần nộp gấp
\(A=\left(4x-1\right)\left(3x+1\right)-5x\left(x-3\right)-\left(x-4\right)\left(x-3\right)\)
\(=\left(4x-1\right)\left(3x+1\right)-\left(5x+x-4\right)\left(x-3\right)\)
\(=12x^2+4x-3x-1-6x^2+4x+18x-12\)
\(=18x^2+19x-13\)