\(\dfrac{5}{6}\) + \(\dfrac{7}{8}\)

=     \(\dfrac{5\times4}{6\times4}\) + \(\dfrac{7\times3}{8\times3}\)

=      \(\dfrac{20}{24}\) + \(\dfrac{21}{24}\)

=         \(\dfrac{41}{24}\)

5/6 + 7/8 = 41/24

2 + 2/3 = 8/3

7/9 - 1/7 = 40/63

1-1/11 =10/11

2x17/81 = 34/81

9/11 : 5/6 = 54/55

3: 12/25 = 25/4

                Tick cho mik nhé.

       Chúc bạn học tốt nha !

2 + \(\dfrac{2}{3}\)

= \(\dfrac{2\times3}{1\times3}\) +  \(\dfrac{2}{3}\)

= \(\dfrac{6}{3}\) + \(\dfrac{2}{3}\)

= \(\dfrac{8}{3}\)

2792/5841

\(=\dfrac{8}{9}\times\dfrac{5}{11}+\dfrac{8}{9}\times\dfrac{6}{11}=\dfrac{8}{9}\times\left(\dfrac{5}{11}+\dfrac{6}{11}\right)=\dfrac{8}{9}\times1=\dfrac{8}{9}\)

=2792/5841

a, 11-(15+11)=x-(25-9)

\(\Leftrightarrow11-26=x-16\)

\(\Leftrightarrow x=-16-11+26\)

\(\Leftrightarrow x=-1\)

b, 2-x=17-(-5)

\(\Leftrightarrow2-x=22\)

\(\Leftrightarrow-x=22-2\)

\(\Leftrightarrow x=-20\)

c, x-(17-x)=x-7

\(\Leftrightarrow x-17+x=x-7\)

\(\Leftrightarrow x+x-x=-7+17\)

\(\Leftrightarrow x=10\)

Bài 1 :

a, Ta có : \(11-\left(15+11\right)=x-\left(25-9\right)\)

=> \(11-15-11-x+25-9=0\)

=> \(x=1\)

b, Ta có : \(2-x=17-\left(-5\right)\)

=> \(2-x=22\)

=> \(x=-20\)

c, Ta có : \(x-\left(17-x\right)=x-7\)

=> \(x-17+x-x+7=0\)

=> \(x=10\)

`a)5/9:(1/11-5/22)+5/9:(1/15-2/3)`

`=5/9:(2/22-5/22)+5/9:(1/15-10/15)`

`=5/9:(-3)/22+5/9:(-9)/15`

`=5/9*(-22)/3+5/9*(-5)/3`

`=5/9*(-22/3+(-5)/3)`

`=5/9*(-9)=-5`

a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)

\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)

=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)

b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)

Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)

c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)

\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)

=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)

d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)

\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6

=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)

  \(\dfrac{1}{2}+\dfrac{3}{4}-\left(\dfrac{3}{4}-\dfrac{4}{5}\right)\)

=\(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}\)

=\(\left(\dfrac{1}{2}+\dfrac{4}{5}\right)+\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\) 

=\(\left(\dfrac{5}{10}+\dfrac{8}{10}\right)+0\)

=\(\dfrac{13}{10}\)

\(-\dfrac{7}{25}.\dfrac{11}{13}+\left(-\dfrac{7}{25}\right).\dfrac{2}{13}-\dfrac{18}{25}\)

=\(-\dfrac{7}{25}.\cdot\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}\) 

=\(-\dfrac{7}{25}.1-\dfrac{18}{25}\) 

=\(-\dfrac{7}{25}-\dfrac{18}{25}\) 

=\(-\dfrac{25}{25}\) = \(-1\)

(-3,2) +\(\dfrac{15}{64}+\left(0.8-2\dfrac{4}{15}\right):3\dfrac{2}{3}\) 

=\(-\dfrac{16}{5}+\dfrac{15}{64}+(\dfrac{4}{5}-\dfrac{34}{15}):\dfrac{11}{3}\)

=\(-\dfrac{16}{5}+\dfrac{15}{64}+(-\dfrac{22}{5}):\dfrac{11}{3}\)

=\(-\dfrac{16}{5}+\dfrac{15}{64}+\dfrac{-2}{5}\)

=(\(-\dfrac{16}{5}+\dfrac{-2}{5}\)) +\(\dfrac{15}{64}\)

=\(-\dfrac{18}{5}+\dfrac{15}{64}\)

\(-\dfrac{1152}{320}+\dfrac{75}{320}\)

\(-\dfrac{1077}{320}\)

đại lượng tỉ lệ nghịch:

đi hết: 6:1,2=5 ( giờ )

a) 12 + 15 + 18 + ... + 90 ( 72 số hạng)

= (12 + 90 ) x 72 : 2

= 3672

b) 8 + 12 + 16 + ... + 100 ( 64 số hạng)

= (8 + 12 ) x 64 : 2 

=640

c) 7 + 11 + 15 + ... + 43 + 47 (14 số hạng )

= (7 + 47 ) x 14 : 2

= 378

d) 1 + 6 + 11 + ........ + 46 + 51 (33 số hạng)

= (1 + 51 ) x 33 : 2

= 858

Công thức tính dãy số có quy luật :

lấy số đầu cộng số cuối nhân số số hạng chia 2

học tốt!!!

a) 12 + 15 + 18 + .. + 90

= (  12 + 90 ) . [( 90 - 12 ) : 3 + 1 ] :2

=       102      .  [    78        : 3  + 1 ] : 2

=        102     .  [          26        +1  ]  : 2

=      102       .          27           : 2

=              2754                          :2

=                          1377

a) 12 + 15 + 18 + ... + 90
= (12 + 90) . [(90 - 12) : 3 + 1] : 2
= (12 + 90 ).27/2 
= 1377

b) 8 + 12 + 16 + ... + 100
= (8 + 100). [(100 - 8) : 4 + 1] : 2
= ( 8 + 100 ).47/2 
= 2538

c) 7 + 11 + 15 + ... + 43 + 47
= (7 + 47). [(47 - 7) : 4 + 1] : 2
= ( 7 + 47 ).11/2
= 297

d) 1 + 6 + 11 + ... + 46 + 51
= (51 + 1). [(51 - 1) : 5 + 1] : 2
= ( 51 + 1 ).26/2 
= 676