\(\dfrac{-5}{6}và\dfrac{-91}{104}\)
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Đề bài: So sánh các số hữu tỉ sau:a)dfrac{-13}{40}vàdfrac{12}{-40}b)dfrac{-5}{6}vàdfrac{-91}{104}c)dfrac{-15}{21}vàdfrac{-36}{44}d)dfrac{-16}{30}vàdfrac{-35}{84}e)dfrac{-5}{91}vàdfrac{-501}{9191}f)dfrac{-11}{3^7.7^3}vàdfrac{-78}{3^7.7^4}giúp mik nha!!!
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Đề bài: So sánh các số hữu tỉ sau:
a)\(\dfrac{-13}{40}và\dfrac{12}{-40}\)
b)\(\dfrac{-5}{6}và\dfrac{-91}{104}\)
c)\(\dfrac{-15}{21}và\dfrac{-36}{44}\)
d)\(\dfrac{-16}{30}và\dfrac{-35}{84}\)
e)\(\dfrac{-5}{91}và\dfrac{-501}{9191}\)
f)\(\dfrac{-11}{3^7.7^3}và\dfrac{-78}{3^7.7^4}\)
giúp mik nha!!!
a: \(\dfrac{-13}{40}< \dfrac{-12}{40}\)
\(\dfrac{-5}{6}>\dfrac{-91}{104}\)
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Trong các phân số sau đây, tìm phân số không bằng các phân số còn lại :
\(\dfrac{15}{35};\dfrac{-6}{33};\dfrac{21}{49};\dfrac{-21}{91};\dfrac{14}{-77};\dfrac{-24}{104};\dfrac{6}{22}\)
BT1: Tính nhanh:
6) 81. \(\dfrac{12-\dfrac{12}{7}-\dfrac{12}{289}-\dfrac{12}{85}}{4-\dfrac{4}{7}-\dfrac{4}{289}-\dfrac{4}{85}}\) : \(\dfrac{5+\dfrac{5}{13}+\dfrac{5}{169}+\dfrac{5}{91}}{6+\dfrac{6}{13}+\dfrac{6}{169}+\dfrac{6}{91}}\). \(\dfrac{158158158}{711711711}\)
\(=81.\dfrac{12.\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}{4.\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}:\dfrac{5.\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}{6.\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}.\dfrac{158}{711}\)
\(=81.\dfrac{12}{4}:\dfrac{5}{6}.\dfrac{2}{9}\)
\(=243:\dfrac{5}{6}.\dfrac{2}{9}\)
\(=\dfrac{1458}{5}.\dfrac{2}{9}\)
\(=\dfrac{324}{5}\)
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tìm x biết
a)x-\(\dfrac{3}{7}\)=\(\dfrac{2}{5}.\dfrac{1}{4}\)
b)x+\(\dfrac{4}{5}\)=\(\dfrac{-5}{12}\).\(\dfrac{3}{25}\)
c)\(\dfrac{x}{182}\)=\(\dfrac{-6}{12}\).\(\dfrac{35}{91}\)
a/ \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{37}{70}\)
Vậy....
b/ \(x+\dfrac{4}{5}=-\dfrac{5}{12}\cdot\dfrac{3}{25}\)
\(x+\dfrac{4}{5}=-\dfrac{1}{20}\)
\(x=-\dfrac{1}{20}-\dfrac{4}{5}=-\dfrac{17}{20}\)
Vậy....
c/ \(\dfrac{x}{182}=-\dfrac{6}{12}\cdot\dfrac{35}{91}\)
\(\dfrac{x}{182}=-\dfrac{5}{26}\)
\(=>x\cdot26=-5\cdot182\)
\(26x=-910\)
\(x=-910:26=-35\)
Vậy....
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a) Ta có: \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(\Leftrightarrow x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{7}{70}+\dfrac{30}{70}\)
hay \(x=\dfrac{37}{70}\)
Vậy: \(x=\dfrac{37}{70}\)
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KN
2 tháng 8 2023 lúc 13:49
bài 1)a)(dfrac{12}{42} - dfrac{26}{91} ).(dfrac{-4}{7} +dfrac{-5}{9})b) dfrac{9}{13} . dfrac{-12}{7} +dfrac{9}{13} .dfrac{29}{17} c) dfrac{4}{7} +dfrac{6}{7} .dfrac{1}{7} +dfrac{1}{7} .dfrac{8}{7} d) (dfrac{5}{7} + dfrac{9}{7} ). dfrac{7}{10} +(dfrac{8}{7} + dfrac{13}{7} ). dfrac{7}{10}
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bài 1)
a)(\(\dfrac{12}{42}\) - \(\dfrac{26}{91}\) ).(\(\dfrac{-4}{7}\) +\(\dfrac{-5}{9}\))
b) \(\dfrac{9}{13}\) . \(\dfrac{-12}{7}\) +\(\dfrac{9}{13}\) .\(\dfrac{29}{17}\)
c) \(\dfrac{4}{7}\) +\(\dfrac{6}{7}\) .\(\dfrac{1}{7}\) +\(\dfrac{1}{7}\) .\(\dfrac{8}{7}\)
d) (\(\dfrac{5}{7}\) + \(\dfrac{9}{7}\) ). \(\dfrac{7}{10}\) +(\(\dfrac{8}{7}\) + \(\dfrac{13}{7}\) ). \(\dfrac{7}{10}\)
a: =(2/7-2/7)(-4/7-5/9)=0
b:
Sửa đề: 9/13*(-12/17)+9/13*29/27
=9/13(-12/17+29/17)
=9/13*17/17=9/13
c: \(=\dfrac{1}{7}\left(4+\dfrac{6}{7}+\dfrac{8}{7}\right)=\dfrac{1}{7}\cdot6=\dfrac{6}{7}\)
d: =7/10(5/7+9/7+8/7+13/7)
=5*7/10=7/2
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NN
20 tháng 12 2022 lúc 15:29
1 so sánh \(\dfrac{1}{2^{300}}\) và \(\dfrac{1}{300^{200}}\)
\(\dfrac{1}{5^{199}}\) và\(\dfrac{1}{3^{300}}\)
2 so sánh
5\(^{20}\)và 3\(^{34}\)
(-5)\(^{39}\)và -2\(^{91}\)
Bài 1:
a: Sửa đề: 1/3^200
1/2^300=(1/8)^100
1/3^200=(1/9)^100
mà 1/8>1/9
nên 1/2^300>1/3^200
b: 1/5^199>1/5^200=1/25^100
1/3^300=1/27^100
mà 25^100<27^100
nên 1/5^199>1/3^300
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-5 -91
___ và ____ So Sánh
6 104
\(-\dfrac{5}{6}=-\dfrac{5.104}{6.104}=-\dfrac{520}{624};-\dfrac{91}{104}=-\dfrac{91.6}{104.6}=-\dfrac{546}{624}\Rightarrow-\dfrac{5}{6}>-\dfrac{91}{104}\)
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Ta có:
\(\dfrac{-91}{104}\) rút gọn cho 13 được \(\dfrac{-7}{8}\)
→ \(\dfrac{-5}{6}=\dfrac{-5.4}{6.4}=\dfrac{-20}{24}\)
\(\dfrac{-7}{8}=\dfrac{-7.3}{8.3}=\dfrac{-21}{24}\)
Vì 20 < 21
nên \(\dfrac{-20}{24}>\dfrac{-21}{24}\)
hay \(\dfrac{-5}{6}>\dfrac{-91}{104}\)
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\(\dfrac{x+1}{94}+\dfrac{x+2}{93}+\dfrac{x+3}{92}\)=\(\dfrac{x+4}{91}+\dfrac{x+5}{90}+\dfrac{x+6}{89}\)
\(\dfrac{x+1}{94}+\dfrac{x+2}{93}+\dfrac{x+3}{92}=\dfrac{x+4}{91}+\dfrac{x+5}{90}+\dfrac{x+6}{89}\)
<=>\(\dfrac{x+1}{94}+1+\dfrac{x+2}{93}+1+\dfrac{x+3}{92}+1=\dfrac{x+4}{91}+1+\dfrac{x+5}{90}+1+\dfrac{x+6}{89}+1\)
<=>\(\dfrac{x+95}{94}+\dfrac{x+95}{93}+\dfrac{x+95}{92}=\dfrac{x+95}{91}+\dfrac{x+95}{90}+\dfrac{x+95}{89}\)
<=>\(\dfrac{x+95}{94}+\dfrac{x+95}{93}+\dfrac{x+95}{92}-\dfrac{x+95}{91}-\dfrac{x+95}{90}-\dfrac{x+95}{89}=0\)
<=> (x+95)(\(\dfrac{1}{94}+\dfrac{1}{93}+\dfrac{1}{92}-\dfrac{1}{91}-\dfrac{1}{90}-\dfrac{1}{89}\))
vì \(\dfrac{1}{94}+\dfrac{1}{93}+\dfrac{1}{92}-\dfrac{1}{91}-\dfrac{1}{90}-\dfrac{1}{89}\) khác 0
=>x+95=0=>x=-95
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\(\dfrac{11}{8}+\dfrac{13}{6}=\dfrac{85}{2x}\)
\(\dfrac{3x}{182}=\dfrac{-6}{14}.\dfrac{35}{91}\)
Tìm x , biết