1) Ta có: \(\sqrt{2x+5}=\sqrt{3-x}\)

\(\Leftrightarrow2x+5=3-x\)

\(\Leftrightarrow2x+x=3-5\)

\(\Leftrightarrow3x=-2\)

hay \(x=-\dfrac{2}{3}\)

2) Ta có: \(\sqrt{2x-5}=\sqrt{x-1}\)

\(\Leftrightarrow2x-5=x-1\)

\(\Leftrightarrow2x-x=-1+5\)

\(\Leftrightarrow x=4\)

3 , \(PT\left(đk:\frac{16}{3}\ge x\ge3\right)< =>x^2-3x=16-3x\)

\(< =>x^2-16=0< =>\left(x-4\right)\left(x+4\right)=0< =>\orbr{\begin{cases}x=4\left(tm\right)\\x=-4\left(ktm\right)\end{cases}}\)

4 , \(PT\left(đk:...\right)< =>2x^2-3=4x-3< =>2x^2-4x=0\)

\(< =>2x\left(x-2\right)=0< =>\orbr{\begin{cases}x=0\left(...\right)\\x=2\left(...\right)\end{cases}}\)

bạn tự tìm đk rồi đối chiếu nhé :P

5, \(PT\left(đk:...\right)< =>\left(2x-7\right)\left(x-2\right)=x-2\)

\(< =>\left(x-2\right)\left(2x-7-1\right)=0\)

\(< =>\orbr{\begin{cases}x=2\\2x-8=0\end{cases}< =>\orbr{\begin{cases}x=2\\x=4\end{cases}}}\)

6, \(PT\left(đk:...\right)< =>x^2-x-6=3x-1\)

\(< =>x^2-4x-5=0< =>\left(x-5\right)\left(x+1\right)=0\)

\(< =>\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)

1: 

max:=a;

if max<b then max:=b;

2: 

min:=a;

if min>b then min:=b;

3: if (x=sqr(a)+sqr(b)) and (a<0) then writeln(x);

if (x=sqrt(b)+sqrt(a)) and (a>0) then writeln(x);

1. I was late for the meeting because of the heavy traffic .
2. He is very intelligent due to the reason that he reads a lot of  books.
3. The car is too expensive so I can't buy it.
4. I broke my mother's favorite vase so she became very angry.
5. There are too many tall building, so we can't see the moon.
6. Since he was lazy, he fell the exam.
7. Because the air is polluted, so many people have breathing problems.
8.They never go out, so they don't know anything outside.
9. Because their parents don't allow them waste money, the children have a lot of saving money.
10. The student's parents always understand them so they feel happy.

bài nào v

có gì đâumà giúp

cập nhật lại bài đi

a: Hàm số nghịch biến trên R

b: \(\dfrac{f\left(x_1\right)-f\left(x_2\right)}{x_1-x_2}=\dfrac{x_1^2-4x_1+5-x_2^2+4x_2-5}{x_1-x_2}\)

\(=x_1+x_2-4\)

Trường hợp 1: x<=2

\(\Leftrightarrow x_1+x_2-4< =0\)

Vậy: Hàm số nghịch biến khi x<=2