x^6 - y^6 = (x^3 -y^3) (x^3 + y^3)

              = (x-y)(x^2 + xy + y^2 )(x+y)(x^2 -xy+ y^2)

\(x^6-y^6\)

\(=\left(x^3-y^3\right)\left(x^3+y^3\right)\)

\(=\left(x.y\right)\left(x^2+xy+y^2\right)\left(x.y\right)\left(x^2-xy+y^2\right)\)

Chúc bạn học tốt!

thank you

Bạn trình bầy rõ ràng chút đi. Mk chẳng hiểu gì cả.

\(-25x^6-y^8+10x^3y^4\\ =-\left(25x^6-10x^3y^4+y^8\right)\\ =-\left[\left(5x^3\right)^2-2\cdot5x^3\cdot y^4+\left(y^4\right)^2\right]\\ \\ =\left(5x^3-y^4\right)^2\)

Ta có

a,    x²-x-y²-y

=x²-y²-(x+y)

=(x-y)(x+y) - (x+y)

=(x+y)(x-y-1)

b,   x²-2xy+y²-z²

=(x-y)²-z²

=(x-y-z)(x-y+z)

con bai 32, 33 neu ban tra loi duoc minh h them

nhanh nha

a)\(x^2+x-6\)

\(=x^2-2x+3x-6\)

\(=\left(x^2-2x\right)+\left(3x-6\right)\)

\(=x\left(x-2\right)+3\left(x-2\right)\)

\(=\left(x-2\right)\left(x+3\right)\)

a) x² + x - 6

= x² - 2x + 3x - 6

= (x² - 2x) + (3x - 6)

= x(x - 2) + 3(x - 2)

= (x + 3)(x - 2)

b) x⁴ + 4

= x⁴ + 4x² + 4 - 4x²

= (x⁴ + 4x² + 4) - 4x²

= (x + 2)² - 4x²

= (x + 2 - 2x)(x + 2 +2x)

Sửa đề: x^4+64

x^4+64

=x^4+16x^2+64-16x^2

=(x^2+8)^2-(4x)^2

=(x^2-4x+8)(x^2+4x+8)

\(=x^4y^4+4x^2y^2+4-4x^2y^2\)

\(=\left(x^2y^2-2\right)^2-\left(2xy^2\right)\)

bn lm tiếp đi

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