(x-3)2 - 4x2 = 0
( x-3 - 2x)( x-3 +2x) =0
(-x-3)(3x-3)=0
\(\left[{}\begin{matrix}-x-3=0\\3x-3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-3\\3x=3\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-3\\x=3:3\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-3\\x=1\end{matrix}\right.\)
Kết luận x \(\in\) { -3;1}
(x-3)2-4x2=0
(x-3-2x)(x-3+2x)=0
⇒\(\left\{{}\begin{matrix}x-3-2x=0\\x-3+2x=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}-x-3=0\\3x-3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-3\\x=1\end{matrix}\right.\)