Question

Tính:

a) (6x³ + 3x² + 4x + 2) : (3x² + 2)

b) (x⁵ + 4x³ + 3x² - 5x + 15) : (x³ - x + 3)

Answer 1

\(\frac{\left(6a^3+3a^2+4a+2\right)}{3a^2+2}=\frac{\left(6a^3+4a\right)+\left(3a^2+2\right)}{3a^2+2}=\frac{2a\left(3a^2+2\right)+\left(3a^2+2\right)}{3a^2+2}=\frac{\left(2a+1\right)\left(3a^2+2\right)}{3a^2+2}=2a+1\)

Answer 2

\(\frac{a^5+4a^3+3a^2-5a+15}{a^3-a+3}=\frac{\left(a^5-a^3+3a^2\right)+\left(5a^3-5a+15\right)}{a^3-a+3}=\frac{a^2\left(a^3-a+3\right)+5\left(a^3-a+3\right)}{a^3-a+3}=a^2+5\)