Question

Tìm x:

\(\left|\sqrt{x}+3\right|-12=2021^0\)

Answer 1

\(\Leftrightarrow\sqrt{x}+3=13\)

hay x=100

Answer 2

\(\Rightarrow\left|\sqrt{x}+3\right|-12=1\)

\(\Rightarrow\left|\sqrt{x}+3\right|=13\)

\(\Rightarrow\left[{}\begin{matrix}\sqrt{x}+3=-13\\\sqrt{x}+3=13\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\sqrt{x}=-16\\\sqrt{x}=10\end{matrix}\right.\) (do \(\sqrt{x}\ge0\)mà -16 < 0) (loại)

\(\Rightarrow x=100\)

Answer 3

cậu tự tính đi nhé

dễ mà