Question

tìm x và y

\(\left(x-2\right)^{2012}+\left|y^2-9\right|^{2014}=0\)

Answer 1

\(\left(x-2\right)^{2012}+\left|y^2-9\right|^{2014}=0\)

ta thấy rằng:

\(\left(x-2\right)^{2012}>=0\)

\(\left|y^2-9\right|^{2014}>=0\)

Để \(\left(x-2\right)^{2012}+\left|y^2-9\right|^{2014}=0\)

Thì (x-2)=0 và |y² - 9|=0

=> x=2 và y= 3

Answer 2

thấy:

\(\left(x-2\right)^{2012}\)≥0;\(\left|y^2-9\right|^{2014}\)≥0

\(\Leftrightarrow\)\(\left(x-2\right)^{2012}=0\) ⇒\(x-2=0\Rightarrow x=2\)

\(\Leftrightarrow\)\(\left|y^2-9\right|^{2014}=0\Rightarrow y^2-9=0\)\(\rightarrow\)\(y^2=9\)

\(\Rightarrow\)\(y=\left\{{}\begin{matrix}3\\-3\end{matrix}\right.\)

Vậy:\(\left[{}\begin{matrix}x=2\\y=3\end{matrix}\right.\) hoàc \(\left[{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)