Question

tìm x hằng đẳng thức 4x^2+4x+1=0

Answer 1

(2x+1)^2=0

2x=-1

x=-1/2

Answer 2

`4x^2+4x+1=0`

`<=>(2x)^2+2.2x+1=0`

`<=>(2x+1)^2=0`

`<=>2x+1=0`

`<=>2x=-1`

`<=>x=-1/2`

Vậy `x=-1/2.`

Answer 3

\(4x^2+4x+1=\left(2x\right)^2+2.2x.1+1^2=\left(2x+1\right)^2=0\Rightarrow2x+1=0\Rightarrow2x=-1\Rightarrow x=-\dfrac{1}{2}\)

Answer 4

Ta có 4x^2+4x+1=0

<=>(2x+1)^2=0

<=>2x+1=0

<=>x=-1/2

tick mik nha