Câu hỏi của Lyly Luta

Question

tìm x biết

(x-3)2-(x+3)2=24

Võ Đông Anh Tuấn · Accepted Answer

$\left(x-3\right)^2-\left(x+3\right)^2=24$

$\Leftrightarrow\left(x-3-x-3\right)\left(x-3+x+3\right)=24$

$\Leftrightarrow-6.\left(2x\right)=24$

$\Leftrightarrow-12x=24$

$\Leftrightarrow x=-2$

Vậy ......Câu trả lời: $\left(x-3\right)^2-\left(x+3\right)^2=24$

$\Leftrightarrow\left(x-3-x-3\right)\left(x-3+x+3\right)=24$

$\Leftrightarrow-6.\left(2x\right)=24$

$\Leftrightarrow-12x=24$

$\Leftrightarrow x=-2$

Vậy ......

Trần Minh Hoàng · Answer

(x - 3)2 - (x + 3)2 = 24

$\Rightarrow$ (x2 - 6x + 32) - (x2 + 6x + 32) = 24

$\Rightarrow$ 0 - 12x = 24

$\Rightarrow$ 12x = -24

$\Rightarrow$ x = -2Câu trả lời: (x - 3)2 - (x + 3)2 = 24

$\Rightarrow$ (x2 - 6x + 32) - (x2 + 6x + 32) = 24

$\Rightarrow$ 0 - 12x = 24

$\Rightarrow$ 12x = -24

$\Rightarrow$ x = -2

Thanh Trà · Answer

$\left(x-3\right)^2-\left(x+3\right)^2=24$

$\left(x-3+x+3\right)\left(x-3-x-3\right)=24$

$x^2-6=24$

$x^2=30$

$x=\sqrt{30}$Câu trả lời: $\left(x-3\right)^2-\left(x+3\right)^2=24$

$\left(x-3+x+3\right)\left(x-3-x-3\right)=24$

$x^2-6=24$

$x^2=30$

$x=\sqrt{30}$

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