(x-2)2-(x-3)(x+3)=6
\(\Rightarrow x^2-8x+16-\left(x^2-4\right)=6\)
\(\Rightarrow x^2-8x+16-x^2+4=6\)
\(\Rightarrow-8x+20=6\)
\(\Rightarrow-8x=-14\)
\(\Rightarrow x=\dfrac{7}{4}\)
Vậy \(x=\dfrac{7}{4}\)
(x-2)2 -(x-3)(x+3)=6
x2-8x+16-(x2-4)=6
x2-8x+16-x2+4=6
-8x+20=6
-8x=-14
x=\(\frac{7}{4}\)
Vậy x =\(\frac{7}{4}\)
Tìm x, biết:
a, (x+8).(x+6)-x^2=104
b, (x+1).(x+2)-(x-3).(x+4)=6
c, 3.(2x-1).(x+2)-2.(3x+2).(x-4)=5
tìm x
1}x+3[x-1]=4 2}2[x-3]+5=3
3}x[x-2]-x^2=-2 4}x^2-x[x+2]=6 5}3x[x-5]-3x[x-3]=6
6}3[x^2-2x+1]+x[2-3x]=7
a, 5*(4x-1)+2*(1-3x)-6*(x+5)=10
b, 2x*(x+1)+3*(x-1)*(x+1)-5x*(x+1)+6x mũ 2 = 0
c, 4*(x-1)*(x+5)-(x+2)*(x+5)-3(x-1)*(x+2)=0
d,2*(5x-8)-3*(4x-5)=4*(3x-4)+11
a. 3[x^2 - 2x +1]+x[2-3x]=7
b. 5[x-2] +2[x+3]=10
c. [x+1][-3]+5[x-4]=-3
d. 2[x-1]-x[3-x]=x^2
đ. 3x[x+5]-2[x+5]=3x^2
e. 4x[x+2]+x[4-x]=3x^2 +12
f. 1/3x [3x+6]-x[x-5]=9
Bài 5: Biết :
a. 3x + 2( 5 - x ) = 0
b. 2x( x + 3 ) + 2( x + 3 ) = 0
Giá trị của x cần tìm là ?
Bài 6: Rút gọn biểu thức:
A = 2x2(-3x3 + 2x2 + x - 1) + 2x(x2 – 3x + 1) giúp mik nhanh dc ko
Tìm X :
A) x.(x-2)-(x+3).x+7+9x=6
B)(3x-5).(7-5x)-(5x+2).(2-3x)=4
C)(x+2).(x mũ2 -2x+4)-(x.3+3)=14x
D)(x mũ2 -x+1).(x+1)-x mũ3 -3x=2
GẤP MN HỘ E ...!!🙂😣
1) Cho x+y=a, x2+y2=b, x3+y3=c
C/m a3-3ab+2c=0
2)Cho x2+y2=1
Tính 2(x6+y6)-3(x4+y4)
Tìm x, biết
a) 4(x+2) - 7(2x-1) + 9(3x-4) = 30
b)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
c) 4x2 + 3(2x2+1) = 2x(5x-7)
d) x(x2-7) = 2x(\(\dfrac{1}{2}\)x2+6) + 8
Tìm x biết : x.(2x2 + x -2 ) - 2x3 - x. (x + 3) - 1 = 4
