Ta có :
|x - 1| \(\ge0\)
|x - 4| \(\ge0\)
=> |x - 1| + |x - 4| \(\ge0\)
=> 3x \(\ge0\)
=> x \(\ge0\)
=> x - 1 + x - 4 = 3x
=> 3x - 2x = -5
=> x = -5
Bài 1,Tìm x,biết:
a, \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b, \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x-9\right|=5\)
Tìm x, biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
tìm x
a ) \(\left|x-1\right|+\left|x-4\right|=3x\)
b \(\left|x+1\right|+\left|x+4\right|=3x\)
Tìm \(x\), biết :
\(\left|x+1\right|+\left|x+4\right|=3x\)
1. Tìm x, biết:
a. \(3x-|x+15|=\frac{5}{4}\)
b. \(\left|x-0,6\right|< \frac{1}{3}\)
c. \(\left|x+\frac{7}{2}\right|\ge\left|-3,5\right|\)
d. \(\left|x-1\right|\le3\frac{1}{4}\)
e. \(\left|2x-1\right|>\left|-\frac{3}{4}\right|\)
1.Tìm x:
a. 4\(\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
Tìm x biết: \(\left|x-\dfrac{1}{3}\right|\)+\(\dfrac{4}{5}\)\(=\left|-3,2+\dfrac{2}{5}\right|\)
Tìm x biết\(\left|x-1\right|+\left|x-4\right|=3x\)
Giúp mik dzới,mik tik cho
Tìm x biết :
b) |x - 1| + 3x = 1
c) |2x - 1 = |2x + 3|
d) |x| + |x +2| = 0
e) \(\left|x.\left(x^2-\dfrac{5}{4}\right)\right|=x\)
