\(4.\left(6x-5\right)-12.\left(2x+1\right)=62\)
=>\(24x-20-24x+12=62\)
=>\(24x+\left(-20\right)+\left(-24x\right)+12=62\)
=>\(\left(24x+\left(-24x\right)\right)+\left(\left(-20\right)+12\right)=62\)
=>\(0+\left(-8\right)=62\)
=>\(-8=62\left(sai\right)\)
=>x∈∅
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\(4x\left(6x-5\right)-12x\left(2x+1\right)=62\)
\(\Leftrightarrow24x^2-20x-24x^2-12x=62\)
\(\Leftrightarrow-32x=62\Leftrightarrow x=\frac{-31}{16}\)
Vậy \(x=-\frac{31}{16}\)
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