Question

Tìm x, biết:

2x - 2y - x^2 + 2xy - y^2 = 0

~ Cảm ơn mọi người nhiều ~

Answer 1

2x – 2y – x² + 2xy – y² = (2x – 2y) – (x² – 2xy + y²)

= 2(x – y) – (x – y)²

= (x – y)[2 – (x – y)]

= (x – y)(2 – x + y)

Answer 2

\(2x-2y-x^2+2xy-y^2=2\left(x-y\right)-\left(x^2-2xy+y^2\right)=2\left(x-y\right)-\left(x-y\right)^2=\left(x-y\right)\left[2-\left(x-y\right)\right]=\left(x-y\right)\left(2x+2y\right)\)