a, 3(x2 - 2x + 1) - 3x( x - 5) = 1
=> 3x2 - 6x + 3 - 3x2 + 15x = 1
=> 9x + 3 = 1
=> x = \(\dfrac{1-3}{9}\) = \(\dfrac{-2}{9}\)
b, (2x)2 + 4x + 1 - 4( x2 + 4x + 4) = 9
=> 4x2 + 4x + 1 - 4x2 - 16x - 16 = 9
=> -12x - 15 = 9
=> x = \(\dfrac{9+15}{-12}\)= -2