Question

tìm x

a, \(2018x-1+2019x\left(1-2018x\right)=0\)

b, \(\left(x+2\right)^3-x^2\left(x-6\right)=4\)

c, \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)

d, \(x^2-5x+4=0\)

Answer 1

Câu a):

ta có (x²-x-2)²+(x-2)²

=((x-2)²(x+1))²+(x-2)²

=(x-2)²(x²+2x+2)

Answer 2

https://i.imgur.com/DxE4HlK.jpg

Answer 3

https://i.imgur.com/t7lbF4T.jpg