Question

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A=\(\frac{63^2-47^2}{215^2-105^2}\) B=\(\frac{437^2-363^2}{537^2-463^2}\) C=(2+1)(2\(^2\)+1)(2\(^4\)+1)(2\(^8\)+1)(2\(^{16}\)+1)

Answer 1

A=\(\frac{63^2-47^2}{215^2-105^2}\)

A=\(\frac{\left(63-47\right).\left(63+47\right)}{\left(215-105\right).\left(215+105\right)}\)

A=\(\frac{16.110}{110.320}\)

A=\(\frac{1760}{35200}\)

\(A=\frac{1}{20}\)

B=\(\frac{437^2-363^2}{537^2-463^2}\)

B=\(\frac{\left(437-363\right).\left(437+363\right)}{\left(537-463\right).\left(537+463\right)}\)

B=\(\frac{74.800}{74.1000}\)

B=\(\frac{4}{5}\)