\(\left(x-1\right)^3-\left(x^3-3x^2-1\right)\)
=\(x^3-3x^2+3x-1-x^3+3x^2+1\)
=\(3x\)
Tick cho mk nha
(x-1)3-(x3-3x2-1)
=x3-3x2+3x-1-(x3-3x2-1)
= x3-3x2+3x-1-x3+3x2+1
= 3x
\(\left(x-1\right)^3-\left(x^3-3x^2-1\right)\)
\(=\left(x-1\right)\left(x^2+x+1\right)-\left(x^3-3x^2-1\right)\)
\(=x^3+x^2+x-x^2-x-1-x^3+3x^2+1\)
\(=3x^2\)