Question

phan tích đa thức thành nhân tử

a) x²+4x+4-y²

b)x¹⁶-4xy+4y²

c)x³+2x²y+xy²

d) 5x+5y-x²-2xy-y²

e) x⁵-x⁴+x³-x²

Answer 1

a)\(x^2+4x+4-y^2=\left(x+2\right)^2-y^2=\left(x+2-y\right)\left(x+2+y\right)\)

b)hình như sai đề

c)\(x^3+2x^2y+xy^2=x^3+x^2y+x^2y+xy^2=\left(x^2+xy\right)\left(x+y\right)=x\left(x+y\right)^2\)

d)\(5x+5y-x^2-2xy-y^2=5\left(x+y\right)-\left(x+y\right)^2=\left(x+y\right)\left(5-x-y\right)\)

e)\(x^5-x^4+x^3-x^2=x^4\left(x-1\right)+x^2\left(x-1\right)=\left(x^4+x^2\right)\left(x-1\right)\)