1,\(x^2\)+\(^{y^2}\)-2xy-4xz+4yz
= (\(x^2-2xy+y^2\))-(4xz-4yz)
= \(^{\left(x-y\right)^2}\)-4z(x-y)
=(x-y)(x-y-4z)
2, \(5x-5y\)-\(2x^2\)+4xy-\(2y^2\)
=(5x-5y) -(\(\)\(2x^2-4xy+2y^2\))
=5(x-y) -2 (\(X^2-2xy+y^2\))
=5(x-y) -2 \(\left(x-y\right)^2\)
=(x-y)(5-2x+2y)
đứng thì like cho mik nha
1. \(x^2+y^2-2xy-4xz+4yz=\left(x-y\right)^2-4z\left(x-y\right)=\left(x-y\right)\left(x-y-4z\right)\)
2. \(5x-5y-2x^2+4xy-2y^2=5x-5y-x^2+2xy-y^2-x^2+2xy-y^2=5\left(x-y\right)-\left(x-y\right)^2-\left(x-y\right)^2=\left(x-y\right)\left(5-x+y-x+y\right)=\left(x-y\right)\left(5-2x+2y\right)\)
1. \(x^2+y^2-2xy-4xz+4yz=\left(x^2-2xy+y^2\right)-4z\left(x-y\right)=\left(x-y\right)^2-4z\left(x-y\right)=\left(x-y\right)\left(x-y-4z\right)\)
2. \(5x-5y-2x^2+4xy-2y^2=5\left(x-y\right)-2\left(x^2-2xy+y^2\right)=5\left(x-y\right)-2\left(x-y\right)^2=\left(x-y\right)\left[5-2\left(x-y\right)\right]=\left(x-y\right)\left(5-2x+2y\right)\)