Question

Help me vs nhen :3

(X+1). (X-1)

(X-2y).(X+2y)

Giúp mình giải vs nha

Chi tiết vs ạ !!!cảm ơn nhiều ạ !!

Answer 1

\(\left(x+1\right)\left(x-1\right)=x^2-x+x-1=x^2-1\)

\(\left(x-2y\right)\left(x+2y\right)=x^2+2xy-2xy-4y^2=x^2-4y^2\)

Answer 2

\(\left(x+1\right).\left(x-1\right)\)

\(=x^2-x+x-1\)

\(=x^2+\left(-x+x\right)-1\)

\(=x^2-1.\)

\(\left(x-2y\right).\left(x+2y\right)\)

\(=x^2+2xy-2xy-4y^2\)

\(=x^2+\left(2xy-2xy\right)-4y^2\)

\(=x^2-4y^2.\)

Chúc bạn học tốt!

Answer 3

1) \((x+1) . (x-1)\) \(= x^2 - x + x - 1\)

\(= x^2 - 1\)

2) \((x-2y).(x+2y)\) \(= x^2 + 2xy - 2xy - 4y^2\)

\(=x^2-4y^2\)

học tốt nhé !