Question

Giúp tui nốt 3 câu này thui pls ;-;

x² - 4x + 4 - x²y + 2xy

x² + 4x - 5

x² + 7x + 12

Xin cảm ơn ạ

Answer 1

Đề là gì bn

Answer 2

1. x² - 4x + 4 - x²y + 2xy

= (x - 2)² - xy(x - 2)

= (x - 2 - xy)(x - 2)

2. x² + 4x - 5

= x² - x + 5x - 5

= x(x - 1) + 5(x - 1)

= (x + 5)(x - 1)

3. x² + 7x + 12

= x² + 3x + 4x + 12 

= x(x + 3) + 4(x + 3)

= (x + 4)(x + 3)

Answer 3

1) \(x^2-4x+4-x^2y+2xy=\left(x-2\right)^2-xy\left(x-2\right)=\left(x-2\right)\left(x-2-xy\right)\)

2) \(x^2+4x-5=x\left(x-1\right)+5\left(x-1\right)=\left(x-1\right)\left(x+5\right)\)

3) \(x^2+7x+12=x\left(x+3\right)+4\left(x+3\right)=\left(x+3\right)\left(x+4\right)\)

Answer 4

b: \(x^2+4x-5=\left(x+5\right)\left(x-1\right)\)

c: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)