Question

Giúp mình với,giải rõ giúp mình ạ

Answer 1

\(a,=x^2+6x+9\\ b,=36-24x+4x^2\\ c,=\left(x^2-16\right)\\ d,=\dfrac{x^2}{4}-4x+16\\ e,=x^2-\dfrac{6}{4}x+\dfrac{9}{16}\\ f,=9x^2+6x+1\\ g,=\left(\dfrac{1}{9}-9x^2\right)\\ h,=x^4-4x^2+4\)

Answer 2

a, \(=x^3+3x^2.3+3.x.9+27=x^3+9x^2+27x+27\)

b, \(=36-24x+4x^2\)

c, \(=\left(x-4\right)\left(x+4\right)=x^2-16\)

d, \(=\dfrac{x^2}{4}-4x+16\)

e, \(=x^3-\dfrac{3.x^2.3}{4}+\dfrac{3.x.9}{16}-\dfrac{9}{16}=x^3-\dfrac{9}{4}x^2+\dfrac{27x}{16}-\dfrac{9}{16}\)

f, \(\left(3x+1\right)^2=9x^2+6x+1\)

g, \(=\dfrac{1}{9}-9x^2\)

h, \(=\left(x-2\right)\left(x+2\right)\)

Answer 3

a: \(=x^2+6x+9\)

b: \(=36-24x+4x^2\)

c: \(=x^2-\dfrac{3}{2}x+\dfrac{9}{16}\)

 

Answer 4

`a)(x+3)^3=x^3 + 3x^2 .3 + 3x .3^2 + 3^3=x^3 +9x^2 +27x+27`

`b)(6-2x)^2=6^2 - 2.6.2x + (2x)^2=36- 24x + 4x^2`

`c)= x^2-16`

`d)=(x^2)/4 - 4x+16`

`e)(x-3/4) ^2= x^2 - 2 .x .3/4 . (3/4)^2=x^2 . 3/2 x . 9/16`