Question

chuyển về dạng tổng hai bình phương: x^2-2x+2+4y^2+4y

Answer 1

`x^2-2x+4y^2+4y+2`

`=x^2-2x+1+4y^2+4y+1`

`=(x-1)^2+(2y+1)^2`

Answer 2

Ta có: \(x^2-2x+2+4y^2+4y\)

\(=x^2-2x+1+4y^2+4y+1\)

\(=\left(x-1\right)^2+\left(2y+1\right)^2\)