a) Ta có: \(125^3\cdot7^4-5^9\cdot49^2:2005^{2006}\)
\(=\left(5^3\right)^3\cdot\left(7^2\right)^2-5^9\cdot49^2:2005^{2006}\)
\(=5^9\cdot49^2-5^9\cdot49^2\cdot\frac{1}{2005^{2006}}\)
\(=5^9\cdot49^2\left(\frac{2005^{2006}-1}{2005^{2006}}\right)\)
Câu 2: Tính
C = \(\dfrac{6^3+3.6^2+3^3}{13}\)
D = \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
BÀI 2 TÍNH :
A = \(\dfrac{6^3+3.6^2+3^3}{13}\)
B = \(\dfrac{4^6.9^5+6^9.120}{8^4-3^{12}.6^{11}}\)
Tính
a)\(\left(5^{-5}\right)^{-1}.\left(\dfrac{1}{2}\right)^{-2}.\dfrac{1}{10^5}\)
b) \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
c) \(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)
\(\dfrac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}\)
A=2^12.3^5-4^6.9^2\(2^2.3)^6+8^4.3^5 - 5^10.7^3-25^5.49^2\(125.7)^3+5^9.14^3
Câu 1: Rút gọn các biểu thức sau:
C = \(\dfrac{8^2.9^5}{3^9.4^3}\)
D = \(\dfrac{81^6.9^5}{27^7.3^{11}}\)
F = \(\dfrac{8^{15}.25^7}{125^5.2^{47}}\)
G = \(\dfrac{10^2.5^3}{8.25^2}\)
a)\(\frac{45^{10}.5^{10}}{75^{10}}\)
b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
c)\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
d) \(\frac{14^{16}.21^{32}.45^{48}}{10^{16}.15^{32}.7^{96}}\)
1,Tính giá trị biểu thức :
A= 212 . 35 - 46 . 92 / (22 . 36 + 84 . 55) - 510 . 73 - 255 . 492 / (125.7)3 + 59 .143
1 tính
a. \((\left|-5\right|7^4+3^2.2\dfrac{2}{5}):(7^5.125.7^3.50)\)
b. \((\dfrac{3^2}{9}.\dfrac{3^3}{81})^{12}:(\dfrac{3^6}{81^2})^{10}\)
c. \([(\dfrac{1}{2})^2.(\dfrac{1}{3})^4.\dfrac{2}{7}]:\left(\dfrac{1}{3}\right)^{-2}.\dfrac{-2^2}{7}\)
