Question

Bài 3: Rút gọn các biểu thức sau:

1) ( x+ 3)(x2 -3x + 9) - (x3 + 54)

2) (2x + y)(4x2 + 2xy + y2 ) - (2x – y)(4x2 + 2xy + y2 )

3) (x – 1)3 – (x + 2)(x2 -2x +4) +3(x +4)(x – 4)

4) x(x + 1)(x - 1) – (x + 1)(x2 – x +1)

5) 8x3 - 5 (2x + 1)(4x2 – 4x + 1)

6) 27 + (x – 3)(x2 +3x + 9)

7) (x – 1)3 – (x +2)(x2 -2x + 4) +3(x +4)(x -4)

8) (x – 2)3 +6( x – 1)2 –(x +1)(x2 -x +1) +3x

Answer 1

1: Ta có: \(\left(x+3\right)\left(x^2-3x+9\right)-\left(x^3+54\right)\)

\(=x^3+27-x^3-54\)

=-27

2: Ta có: \(\left(2x+y\right)\left(4x^2-2xy+y^2\right)-\left(2x-y\right)\left(4x^2+2xy+y^2\right)\)

\(=8x^3+y^3-8x^3+y^3\)

\(=2y^3\)​

Answer 2

\(1,=x^3+270-x^3-54=-27\\ 2,=8x^3+y^3-8x^3+y^3=2y^3\\ 3,=x^3-3x^2+3x-1-x^3-8+3x^2-48=3x-57\\ 4,=x^3-x-x^3-1=-x-1\\ 5,=8x^3-5\left(8x^3+1\right)=-32x^3-5\\ 6,=27+x^3-27=x^3\\ 7,làm.ở.câu.3\\ 8,=x^3-6x^2+12x-8+6x^2-12x+6-x^3-1+3x\\ =3x-3\)