Bài 5: Lũy thừa của một số hữu tỉ

PH

bài 3: giúp mình với làm ơn

a, 1,25 . \(\left[-3\frac{3}{8}\right]\) b, \(\frac{-9}{34}.\frac{17}{4}\)

c, \(\frac{-20}{41}.\frac{-4}{5}\) d, \(\frac{-6}{7}.\frac{21}{2}\)

bài 4:

a, \(\frac{-5}{2}.\frac{3}{4}\) b,\(4\frac{1}{5}:\left[-2\frac{4}{5}\right]\)

c,\(1,8:\left[\frac{-3}{4}\right]\) d,\(\frac{17}{15}:\frac{4}{3}\)

NT
26 tháng 9 2020 lúc 19:03

Bài 3:

a) Ta có: \(1.25\cdot\left(-3\frac{3}{8}\right)\)

\(=\frac{5}{4}\cdot\frac{-27}{8}\)

\(=\frac{-135}{32}\)

b) Ta có: \(\frac{-9}{34}\cdot\frac{17}{4}\)

\(=\frac{-9}{4}\cdot\frac{17}{34}\)

\(=-\frac{9}{4}\cdot\frac{1}{2}\)

\(=-\frac{9}{8}\)

c) Ta có: \(-\frac{20}{41}\cdot\frac{-4}{5}\)

\(=\frac{20}{41}\cdot\frac{4}{5}\)

\(=\frac{16}{41}\)

d) Ta có: \(\frac{-6}{7}\cdot\frac{21}{2}\)

\(=-\frac{6}{2}\cdot\frac{21}{7}\)

\(=-3\cdot3=-9\)

Bài 4:

a) Ta có: \(-\frac{5}{2}\cdot\frac{3}{4}\)

\(=-\frac{5\cdot3}{2\cdot4}=\frac{-15}{8}\)

b) Ta có: \(4\frac{1}{5}:\left(-2\frac{4}{5}\right)\)

\(=-\frac{21}{5}:\frac{14}{5}\)

\(=-\frac{21}{5}\cdot\frac{5}{14}\)

\(=-\frac{21}{14}=-\frac{3}{2}\)

c) Ta có: \(1.8:\left(-\frac{3}{4}\right)\)

\(=\frac{9}{5}:\frac{-3}{4}\)

\(=\frac{9}{5}\cdot\frac{4}{-3}\)

\(=-\frac{12}{5}\)

d) Ta có: \(\frac{17}{15}:\frac{4}{3}\)

\(=\frac{17}{15}\cdot\frac{3}{4}\)

\(=\frac{17}{20}\)

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