Bài 2:
a) \(B=x^2+x-11\)
\(=x^2+2.\frac{1}{2}.x+\frac{1}{4}-\frac{45}{4}\)
\(=\left(x+\frac{1}{2}\right)^2-\frac{45}{4}\ge-\frac{45}{4}\)
Dâu = xảy ra khi:
\(\left(x+\frac{1}{2}\right)^2=0\)
\(\Rightarrow x+\frac{1}{2}=0\)
\(\Rightarrow x=0-\frac{1}{2}=-\frac{1}{2}\)
b) \(C=x^2-8x+1\)
\(=x^2-2.4.x+16-15\)
\(=\left(x-4\right)^2-15\ge-15\)
Dấu = xảy ra khi:
\(\left(x-4\right)^2=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=0+4=4\)
Ko chắc à!
Đúng 0
Bình luận (0)