Bài 1 :
\(\left(3x-2\right)^2+\left(x-1\right)\left(2x+4\right)=9x^2-12x+4+2x^2+4x-2x-4=11x^2-10x=x\left(11x-10\right)\)
Bài 2 :
a) \(\left(2x+5\right)^2-4x\left(x+1\right)=3\)
=> \(4x^2+20x+25-4x^2-4x=3\)
\(\Rightarrow16x=-22\)
\(\Rightarrow x=-\frac{11}{8}\)
b) \(\left(2x-3\right)^2-\left(2x+1\right)\left(x+2\right)=0\)
\(\Rightarrow4x^2-12x+9-2x^2-4x-x-2=0\)
\(\Rightarrow2x^2-17x+7=0\)
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