5^n+1-2.5^n
2x^n-1(x^n+1-y^n+1)+y^n+1(2x^n-1-y^n-1)
3x^n(ax^n-1-1)-2x^n+1(6x^n-2-1)
3^n+1-2*3^n
3^10.2^10-6^7.(6^3+1)
6). – x2 y(xy2 – 1/2 xy + 3/4 x2 y2 )
7). (3xy – x2 + y). 2/3 x2 y
8). (4x3 – 5xy + 2x)( – 1/2 xy)
9). 2x2 (x2 + 3x + 1/2 )
10). – 3/2 x4 y2 (6x4 − 10/9 x2 y3 – y5 )
11). 2 3 x3 (x + x2 – 3/4 x5 )
12). 2xy2 (xy + 3x2 y – 2/3 xy3 )
13). 3x(2x3 – 1/3 x2 – 4x)
14). 3/5 x3 y5 (7x4 + 5x2 y − 10/21 x4 y3 –y4 )
tìm x
1}x+3[x-1]=4 2}2[x-3]+5=3
3}x[x-2]-x^2=-2 4}x^2-x[x+2]=6 5}3x[x-5]-3x[x-3]=6
6}3[x^2-2x+1]+x[2-3x]=7
BÀI 2: rút gọn biểu thức
a) 2x( 5-3x^2) - 10( 6+x)
b)3(-x+2)-6( 1-x+5x^20)
c) 7x( 2-5x^2+1/2x^3)- 14x( 1-2x^2)
tìm x
a, \(\frac{5}{6}=\frac{-1}{x}\)
b,\(\frac{-3}{7}=\frac{x}{14}\)
c,\(\frac{x+1}{4}=\frac{-3}{2}\)
d,\(\frac{2x-3}{5}=\frac{-6}{7}\)
e,\(\frac{3-5x}{4}=\frac{5}{6}\)
f,\(\frac{12}{x}=\frac{-6}{5}\)
a. 3[x^2 - 2x +1]+x[2-3x]=7
b. 5[x-2] +2[x+3]=10
c. [x+1][-3]+5[x-4]=-3
d. 2[x-1]-x[3-x]=x^2
đ. 3x[x+5]-2[x+5]=3x^2
e. 4x[x+2]+x[4-x]=3x^2 +12
f. 1/3x [3x+6]-x[x-5]=9
tìm x
\(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-10\)
\(6^2. 6^4-4^3(3^6-1)\)
Tìm x:
1/ 4.(18-5x)-12.(3x-7)=15.(2x-16)-6.(x+14) 2/5.(3x+5)-4(2x-3)=5x+3.(2x+12)+1 3/2.(5x-8)-3(4x-5)=4(3x-4)+11 4/5x-3.{4x-2.[4x-3(5x-2)]}=182
