\(\left(2-x\right)^2-\left(x-2\right)\left(3+x\right)=4-4x+x^2-x^2-x+6=-5x+10\)
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Bài 3: Những hằng đẳng thức đáng nhớ
Các câu hỏi tương tự
(x+2)^2-2x(x+1)+(x-3)(x+3)
(x+2y)(x^2-2xy+4y^2)-(x-2y)(x^2+2xy+4y^2)+2y^3
(3+x)(x^2-9)-(x-3)(x^2+3x+9)
(x-y)^3-(x-y)(x^2+xy+y^2)
tìm x biết:
a) (x-3)2-4=0
b) x2-2x=24
c) (x+4)2-(x+1)(x-1)=16
d) (2x+1)2-4(x-1)2=9
e) (x+3)2-(x-4)(x+8)=1
f) (2x-1)2+(x+3)2-5(x+7)(x-7)=0
g) 3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
Tìm x biết
a,(x+4)^2-(x+1)(x-1)=16
b,(2x-1)^2-(x+3)-5(x-7)(x+7)=0
c,3(x-1)^2-3x(x-5)=1
d,6(x-2)^2+(5x-2)^2-4(3x-1)(5x-2)=0
e,(x-2)^3-x^2(x-6)=4
g,(x-1)(x^2+x+1)-x(x+2)(x-2)=5
h,(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Rút gọn
1 (x-2)^2 + (x+3)^2-2.(x+1).(x-1)
2 ( x-y).(x+y).(x^2 +y^2).(x^4 + y^4)
3 3.(x-y)^2-2(x+y)^2+(x+y).(x-y)
4 (x-1)^2 -2(x-1)(x-3)+(x-3)^2
Tìm x, biết:
a) 6(x + 2)(x - 3) - 3(x - 2)2 - 3(x - 1)(x + 1) = 1
b) (x - 1)(x2 + x + 1) + x(x + 2)(2 - x) = 5
c) (x - 1)3 - (x + 3)(x3 - 3x + 9) + 3(x - 2)(2 + x) = 2
1, tìm x :
a) (x+2).(x+3)-(x-2).(x+5)=0
b) (2x+3).(x-4)+(x-5).(x-2)=(x-4).(3x-5)
c) (3x-5).(7-5x)-(5x+2).(2-3x)=3
d)(x-7).(x+7)-(x-4)2-x=10+3
e) (x+1/2)2-(x-1).(x+1)=2x-1
2, Thu gọn :
a) (x+5)2-(3-x)2-2(x-4).(x+4)
b)4(x-1)2+(2x+3)2-8(x-2)(x+2)
tìm x (x-1)^3+3(x-3)^2-(x+2)(x^2-2x+4)=(x+2)^2-(x-3)(x^2+9)-6x^2+5
Tìm x biết
1) 8x ^ 3 - 12x ^ 2 + 6x - 1 = 0
2) x ^ 3 - 6x ^ 2 + 12x - 8 = 27
3) x ^ 2 - 8x + 16 = 5 * (4 - x) ^ 3
4) (2 - x) ^ 3 = 6x(x - 2)
5) (x + 1) ^ 3 - (x - 1) ^ 3 - 6 * (x - 1) ^ 2 = - 10
6) (3 - x) ^ 3 - (x + 3) ^ 3 = 36x ^ 2 - 54x
1; Thực hiện phép tính.
1, (x+1).(x-2).(x-3)^2
2, x.(x+1)-(x+2).(x-3)
3, (x+2)^2 -(x-2)^2
4, (x+1)^3-(x-1)^3
5,( x+y)^3 -(x-y)^3
6, (x-3).(x+3)-(x-1)^2
7, (x+1).(x-1).(x^2+1).(x^4+1)-x^8
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DB
2 tháng 10 2020 lúc 18:48
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+2)(x^2-2x+4)-x(x^2+2)=15
c)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
d)(x^2-1)^3-(x^4+x^2+1)(x^2-1)=0