\(\left(x-2\right)^3+\left(5-2x\right)^3=0\)
\(\Leftrightarrow\left(x-2+5-2x\right)\left[\left(x-2\right)^2-\left(x-2\right)\left(5-2x\right)+\left(5-2x\right)^2\right]=0\)
\(\Leftrightarrow\left(3-x\right)\left(x^2-4x+4+2x^2-9x+10+4x^2-20x+25\right)=0\)
\(\Leftrightarrow\left(3-x\right)\left(7x^2-33x+39\right)=0\)
\(\Leftrightarrow3-x=0\)
\(\Leftrightarrow x=3\)
Vậy \(S=\left\{3\right\}\)
Wish you study well !!
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