a/ \(3x^2\left(4x^3-2x+\dfrac{1}{3}\right)=12x^5-6x^3+x^2\)
b/ \(\left(4x^2+8xy-3xy^2\right)\left(-\dfrac{3}{4}x^2y\right)\)
\(=-3x^4y-6x^3y^2+\dfrac{9}{4}x^3y^3\)
c/ \(4x^3\left(2x^2-x+5\right)5x=20x^4\left(2x^2-x+5\right)\)
\(=40x^6-20x^5+100x^4\)
a, \(3x^2\left(4x^3-2x+\dfrac{1}{3}\right)\)
\(=12x^5-6x^3+x^2\)
b, \(\left(4x^2+8xy-3xy^2\right).\left(\dfrac{-3}{4}x^2y\right)\)
\(=-3x^4y-6x^3y^2+\dfrac{9}{4}x^3y^3\)
c, \(4x^3\left(2x^2-x+5\right)5x\)
\(=\left(8x^5-4x^4+20x^3\right)5x\)
\(=40x^6-20x^5+100x^4=20x^4.\left(2x^2-x+5\right)\)
Chúc bạn học tốt!!! Mình không chắc đâu !
\(a,3x^2\left(4x^3-2x+\dfrac{1}{3}\right)=12x^5-6x^3+x^2\) \(b,\left(4x^2+8xy-3xy^2\right)\left(\dfrac{-3}{4}x^2y\right)=-3x^4y-6x^3y^2+\dfrac{9}{4}x^3y^3\)
\(c,4x^3\left(2x^2-x+5\right)5x=20x^4\left(2x^2-x+5\right)=40x^6-20x^5+100x^4\)
a) \(3x^2\left(4x^3-2x+\dfrac{1}{3}\right)\)
\(=12x^5-6x^3+x^2\)
b) \(\left(4x^2+8xy-3xy^2\right)\left(-\dfrac{3}{4}x^2y\right)\)
\(=-3x^4y-6x^3y^2+\dfrac{9}{4}x^3y^3\)
c) \(4x^3\cdot\left(2x^2-x+5\right)\cdot5x\)
\(=4x^3\cdot5x\cdot\left(2x^2-x+5\right)\)
\(=20x^4\cdot\left(2x^2-x+5\right)\)
\(=40x^6-20x^5+100x^4\)