Tim x 3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=36
(x + 2)^2 + (2x -1)^2-(x - 3)^2 = 36
(2x -1)2 + (x + 3)2 - 5(x + 7)(x - 7) = 0
tìm x biết:
a) (x-3)2-4=0
b) x2-2x=24
c) (x+4)2-(x+1)(x-1)=16
d) (2x+1)2-4(x-1)2=9
e) (x+3)2-(x-4)(x+8)=1
f) (2x-1)2+(x+3)2-5(x+7)(x-7)=0
g) 3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
Bài 3: Tìm x biết:
1, \(4x^2-36=0\)
2, \(\left(x-1\right)^2+x\left(4-x\right)=11\)
3, \(\left(x-5\right)^2-x.\left(x+2\right)=5\)
4, \(x\left(x+4\right)-x^2-6x=10\)
Tìm x biết
1) 8x ^ 3 - 12x ^ 2 + 6x - 1 = 0
2) x ^ 3 - 6x ^ 2 + 12x - 8 = 27
3) x ^ 2 - 8x + 16 = 5 * (4 - x) ^ 3
4) (2 - x) ^ 3 = 6x(x - 2)
5) (x + 1) ^ 3 - (x - 1) ^ 3 - 6 * (x - 1) ^ 2 = - 10
6) (3 - x) ^ 3 - (x + 3) ^ 3 = 36x ^ 2 - 54x
Viết các biểu thức sau dưới dạng tích
a. x^4+4,x^2+4;9a^4+35a^2b^2+16b^4
b. 4a^2b^2-c^2d^2;a^3+27;x^16-y^16
c. x^3-125;-64+\(\dfrac{1}{8}\) x^3
d. 8x^3+60x^2y+150xy^2+125y^3
giúp mình nhé!
tìm x biết
phần a: (2x+1)^2= 25 ; (2x-3)^2= 36
phần b: 5^x+2= 625 ; (2x -1)^3= -8
phần c: (x-3)^2+(15x-45)^4= 0 ; |x-3|+(x^2-3x)^2= 0
Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
(x-3).(x+3)- (x-6)^2
(x+1)^2+(x-1)^2- (x-1).(x-1)
(x+4).(x-4).(x^2+16)
(2+1).(2^2+1).(2^4+1).(2^8+1)
Giúp mình với ạ!
