b) Ta có: \(\dfrac{4}{7}+\dfrac{3}{7}\cdot\dfrac{-2}{3}\)
\(=\dfrac{4}{7}-\dfrac{2}{7}\)
\(=\dfrac{2}{7}\)
c) Ta có: \(\dfrac{9^2\cdot3^3}{3^7}\cdot2018^0\)
\(=\dfrac{3^4\cdot3^3}{3^7}\)
=1
e) Ta có: \(3-\left(-\dfrac{7}{8}\right)^0+\left(\dfrac{1}{2}\right)^3\cdot16\)
\(=3-1+\dfrac{1}{8}\cdot16\)
=2+2
=4
Đúng 2
Bình luận (0)
