Sau khi thực hiện phép tính \(\left[3\left(x-y\right)^6+3\left(x-y\right)^4-4\left(x-y\right)^2\right]:\left(x-y\right)^2\) , ta có kết quả là
\(3\left(x-y\right)^4+3\left(x-y\right)^2-4\) \(3\left(x-y\right)^4-3\left(x-y\right)^2-4\) \(3\left(x-y\right)^4+3\left(x-y\right)^2+4\) \(\left(x-y\right)^4+\left(x-y\right)^2-4\) Hướng dẫn giải:\(\left[3\left(x-y\right)^6+3\left(x-y\right)^4-4\left(x-y\right)^2\right]:\left(x-y\right)^2\)
\(=3\left(x-y\right)^4+3\left(x-y\right)^2-4\)
