Thu gon cac bieu thuc sau
7x - 19x + 6x
-ab - ab
H24
Những câu hỏi liên quan
Thu gon bieu thuc sau
7x-19x+6x
-ab-ab
Lm giup mk voi dag gap
x+2x+4x+...+125x+126x bang cach thu gon cac bieu thuc sau:
Đề không đúng
Tự dưng 1x+2x+4x+......+125x + 126x là sao
Đúng 0
Bình luận (0)
Rut gon cac bieu thuc sau
A) 2x^2(1-3x)+6x^3
B) (x-y)^2+(x+y)^2+2(x-y)(x+y)
A) 2x2(1-3x)+6x3
=2x2*(1-3x)+2x2*3x
=2x2*(1-3x+3x)
=2x2
B) (x-y)2+(x+y)2+2(x-y)(x+y)
=2(x2-y2)+x2+2xy+y2+x2-2xy+y2
=2x2-2y2+x2+2xy+y2+x2-2xy+y2
=4x2
Đúng 0
Bình luận (0)
cho a,b,c khac nhau doi mot va 1/a+1/b+1/c=0.rut gon cac bieu thuc
N=bc/a^2+2bc+CA/B^2+2AC+AB/C^2+2AB
rut gon bieu thuc (6x-1)^2+(6x+1)^2-2(1+6x)(6x+1)
cho bieu thuc A=\(\left(\dfrac{6x+4}{3\sqrt{3x^3}-8}-\dfrac{\sqrt{3x}}{3x+2\sqrt{3x}+4}\right)\left(\dfrac{1+3\sqrt{3x^3}}{1+\sqrt{3x}}-\sqrt{3x}\right)\)
a.rut gon bieu thuc A
b. tim cac gia tri nguyen x de A nguyen
a: \(A=\left(\dfrac{6x+4}{\left(\sqrt{3x}-2\right)\left(3x+2\sqrt{3x}+4\right)}-\dfrac{\sqrt{3x}}{3x+2\sqrt{3x}+4}\right)\left(\dfrac{1+\left(\sqrt{3x}\right)^3}{1+\sqrt{3x}}-\sqrt{3x}\right)\)
\(=\dfrac{6x+4-3x+2\sqrt{3x}}{\left(\sqrt{3x}-2\right)\left(3x+2\sqrt{3x}+4\right)}\cdot\left(1-\sqrt{3x}\right)^2\)
\(=\dfrac{\left(\sqrt{3x}-1\right)^2}{\sqrt{3x}-2}\)
b: Để A là số nguyên thì \(3x-2\sqrt{3x}+1⋮\sqrt{3x}-2\)
=>\(\sqrt{3x}-2\in\left\{1;-1;3;-3\right\}\)
=>\(3x\in\left\{9;1;25\right\}\)
hay x=3
Đúng 0
Bình luận (0)
thu gon cac bieu thuc sau
1215*98*1254
119 * 3 16*255
rút gon cac bieu thuc (2x +3) mũ 2-(2x+5) mũ 2
(2x+3)2-(2x+5)2
= 4x2+12x+32-4x2+20x+52
=12x+9-12x-8x-25
=9-8x-25
=(-16)-8x
Đúng 0
Bình luận (0)
rut gon bieu thuc (6x+7)(2x-3)-(4x+1)(3x-7/4)