nhầm, cái này đúng nhất

10+(2x-1)²:3=13

(2x-1)²:3=13-10

(2x-1)²:3=3

(2x-1)²=3x3

(2x-1)²=9

(2x-1)²=3²

=>2x-1=3

2x=3+1

2x=4

x=4:2

x=2

10+(2x-1)²:3=12

(2x-1)²:3=12-10

(2x-1)²:3=2

(2x-1)²=2x3

(2x-1)²=6

đề sai

10+(2x-1)²:3=13

(2x-1)²:3=13-10

(2x-1)²:3=3

(2x-1)²=3.3

(2x-1)²=9

(2x-1)²=3²

=>2x-1=3

2x=3+1

2x=4

x=4:2

x=2

a. x=1

b. x=1

a. x = 1

b. x = 1

a,x=\(\frac{4}{3}\)

b, x= 1

c, x= viết đề rõ hơn

d, \(\frac{13}{6}\)

a,10x+65=125

   10x      =125-65

       x      =60:10

       x      =6

Vậy:...

b,45-(5-2x)^3=2.3^2

   45-(5-2x)^3=18

    (5-2x)^3    =45-18

    (5-2x)^3    =27=3^3

=> 5-2x  = 3

     2x = 5-3

     x= 2:2

     x=1

Vậy:....

-Hok tốt ~ K mk nhak.

a, 10x + 65 = 125

10x = 125 - 65

10x = 60

x = 60 : 10

x = 6

b,45-(5-2x)^3=2.3^2

45 - ( 5 - 2x )^3 =18

(5 - 2x)^3 = 45 - 18

(5 - 2x )^3= 3^3

5 - 2x = 3

2x = 2

x = 1

c,2(x-3)-12=(-10)

2x - 6 -12 =-10

2x = -10 + 6 + 12

2x = 8

x = 4

d,x-12=(-13)+1+|-13|

x - 12 = -13 + 1 + 13

x - 12 = 1

x = 13

hok tốt!!!

\(\text{a)}\)\(10x+65=125\)

\(\Rightarrow10x=60\)

\(\Rightarrow x=6\)

\(b\text{)}\)\(45-\left(5-2x\right)^3=2.3^2\)

\(\Rightarrow45-\left(5-2x\right)^3=18\)

\(\Rightarrow\left(5-2x\right)^3=45-18\)

\(\Rightarrow\left(5-2x\right)^3=27\)

\(\Rightarrow\left(5-2x\right)^3=3^3\)

\(\Rightarrow5-2x=3\)

\(\Rightarrow2x=2\Rightarrow x=1\)

a: \(\Leftrightarrow\left|x-1\right|=3-2x\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-3-x+1\right)\left(2x+3+x-1\right)=0\\x< =\dfrac{3}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left(x-2\right)\left(3x+2\right)=0\\x< =\dfrac{3}{2}\end{matrix}\right.\)

=>x=-2/3

b: Trường hợp 1: x<-3

Pt sẽ là:

\(-x-1-x-3=10-4x\)

=>-2x-4=10-4x

=>2x=14

hay x=7(loại)

Trường hợp 2: -3<=x<-1

Pt sẽ là \(x+3-x-1=10-4x\)

=>10-4x=2

=>4x=8

hay x=2(loại)

Trường hợp 3: x>=-1

Pt sẽ là x+1+x+3=10-4x

=>2x+4=10-4x

=>6x=6

hay x=1(nhận)

a/ x = 4

a) 2^x.(1 + 2³) = 144

2^x . 9 = 144

2^x = 16

=> x = 4

b) (2x - 1)¹⁰ = (2x - 1)¹⁰⁰

(2x - 1)¹⁰⁰ - (2x - 1)¹⁰  = 0

 (2x - 1)¹⁰.[ (2x - 1)⁹⁰ - 1] = 0

=>  (2x - 1)¹⁰ = 0 hoặc  (2x - 1)⁹⁰ - 1 = 0

=> 2x = 1   hoặc    (2x - 1)⁹⁰ = 1

=> x = \(\frac{1}{2}\)  hoặc   \(2x-1=\orbr{\begin{cases}1\\-1\end{cases}}\)

=>                             \(2x=\orbr{\begin{cases}2\\0\end{cases}}\)

=> x = {\(\frac{1}{2};1;0\)}

\(a,\frac{-3}{2}-2x+\frac{3}{4}=-1\)

\(\frac{-3}{2}-2x=-1-\frac{3}{4}\)

\(\frac{-3}{2}-2x=\frac{-7}{4}\)

\(2x=\frac{-7}{4}+\frac{-3}{2}\)

\(2x=\frac{-13}{4}\)

\(x=\frac{-13}{4}:2\)

\(x=\frac{-13}{4}.\frac{1}{2}\)

\(x=\frac{-13}{8}\)

Câu 1: C

Câu 2: A

Câu 3: C