Phan tich da thuc sau ra thua so: x5 - 8x4 + 21x3 - 34x2 + 80x -96
Phan tich da thuc da thuc sau ra thua so : P(x) = x5 - 8x +21x3 - 34x2 + 8x -96
Phan tich da thuc sau ra thua so nguyen to: a2 -6a3 + 27a2 - 54a +32
\(a^4-6a^3+27a^2-54a+32\)
\(=\left(a^4-a^3\right)-\left(5a^3-5a^2\right)+\left(22a^2-22a\right)-\left(32a-32\right)\)
\(=\left(a-1\right)\left(a^3-5a^2+22a-32\right)\)
Phân tích đa thức thành nhân tử chứ
tinh gia tri bieu thuc roi phan tich ket qua ra thua so nguyen to
250x5:2=...
phan tich ra thua so nguyen to:....
= 625
625= 54
Vì 5*5*5*5 = 625
Phan tich da thuc sau ra thua so
x2+4
(x+2)(x+3)(x+4)(x+5)-24
Ta có \(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24=\text{[}\left(x+2\right)\left(x+5\right)\text{]}.\text{[}\left(x+3\right)\left(x+4\right)\text{] -24}\)
\(=\left(x^2+7x+10\right)\times\left(x^2+7x+12\right)-24\)
Đặt \(x^2+7x+10=y\)
\(x^2+7x+12=y+2\)
\(\Rightarrow y\left(y+2\right)-24=y^2+2y-24\)
\(=y^2-4y+6y-24\)
\(=y\left(y-4\right)+6\left(y-4\right)\)
\(=\left(y-4\right)\left(y+6\right)\left(1\right)\)
Thay\(y=x^2+7x+10\) vào (1) ta được
\(\left(x^2+7x+10-4\right)\left(x^2+7x+10+6\right)\)
\(=\left(x^2+7x+6\right)\left(x^2+7x+16\right)\)
\(=\left(x^2+x+6x+6\right)\left(x^2+7x+16\right)\)
\(=\text{[}x\left(x+1\right)+6\left(x+1\right)\text{]}\left(x^2+7x+6\right)\)
\(=\left(x+1\right)\left(x+6\right)\left(x^2+7x+6\right)\)
Vậy \(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24=\left(x+1\right)\left(x+6\right)\left(x^2+7x+6\right)\)
tinh gia tri bieu thuc roi phan tich ket qua ra thua so nguyen to:
(1234+16) : 2
1234+16=1250
1250:2=625
phân tích ra thừa số nguyên tố
625=54
a)Khong thuc hien phep tinh xet xem tong sau co chia het cho 9 khong? A=270+3105+150; B=504+1378+612
b)Phan tich cac so ra thua so nguyen to:36;98;39;72
Suy ra A ko chia hết cho 9
2. Làm tương tự câu a
b, 36=22 x32
98=2x72
39=3x13
72=23x32
THẾ đc rùi nha!
khi thuc hien phep nhan 2 thua so, mot ban da viet nham 2 chu so cuoi cung cua thua so thu 1 la 35 thanh 53 nen co ket qua la 22197.tim 2 thua so da cho, biet rang tich dung cua chung la 21315
phan tich cac da thuc sau thanh phan tu
6x^2+12xy+5x+10y
\(=6x\left(x+2y\right)+5\left(x+2y\right)=\left(6x+5\right)\left(x+2y\right)\)
\(=6x\left(x+2y\right)+5\left(x+2y\right)=\left(x+2y\right)\left(6x+5\right)\)
khi thuc hien mot phep nhan 2 so, mot ban hoc sinh viet nham chu so 4 o hang don vi cua mot thua sothanh chu so 1 ,vi the ban do da tim ra ket qua la 525.hay tim hai so da cho biet tich dung la 600