a:

=x(x²-y²-10x+25)

=x((x²-10x+25)-y²)

=x((x-5)²-y²)

=x(x-5-y)(x-5+y)

b

=>8x(x-5)-3(x-5)=0

=>(x-5)(8x-3)=0

x-5=0=>x=5 hoặc 8x-3=0=>x=3/8

a) Ta có: \(x^2-3x+xy-3y\)

\(=x\left(x-3\right)+y\left(x-3\right)\)

\(=\left(x-3\right)\left(x+y\right)\)

b) Ta có: \(x^3+10x^2+25x-xy^2\)

\(=x\left(x^2+10x+25-y^2\right)\)

\(=x\left(x+5-y\right)\left(x+5+y\right)\)

c) Ta có: \(x^3+2+3\left(x^3-2\right)\)

\(=4x^3-4\)

\(=4\left(x-1\right)\left(x^2+x+1\right)\)

a) \(5x^3-10x^2+15x=5x\left(x^2-2x+3\right)\)

b) \(x^2-3x+2=x\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x-1\right)\)

a: \(=5x\left(x^2-2x+3\right)\)

b: =(x-1)(x-2)

1a) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

b) \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

\(a,=-\left(x-1\right)^3\left[=\left(1-x\right)^3\right]\\ b,=\left(1-x\right)^3\)

a. \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

b. \(=\left(1-x\right)^3\)

\(27y^3-x^3\\=(3y)^3-x^3\\=(3y-x)[(3y)^2+3y\cdot x+x^2]\\=(3y-x)(9y^2+3xy+x^2)\)

a) \(24x^2-4xy\)

\(=4x\left(6x-y\right)\)

b) \(5x^3-10x^2+5x-20xy^2\)

\(=5x\left(x^2-10x+5-20y^2\right)\)

nhầm câu b nha 

\(5x^3-10x^2+5x-20xy^2\)

\(=5x\left(x^2-2x+1-\left(2y\right)^2\right)\)

\(=5x\left(\left(x-1\right)^2-\left(2y\right)^2\right)\)

\(=5x\left(x-1-2y\right)\left(x-1+2y\right)\)

x3 – 2x2 + x

= x.x2 – x.2x + x (Xuất hiện nhân tử chung là x)

= x(x2 – 2x + 1) (Xuất hiện hằng đẳng thức (2))

= x(x – 1)2

\(x^3+2x^2+x\)

\(=x\left(x^2+2x+1\right)\)

\(=x\left(x+1\right)^2\)

\(x\left(x^2+2x+1\right)=x\left(x+1\right)^2\)