2.3^x + 3^2+x=891 tim x
x+x+x+5*x+5+2=891
tim x=?
x(1+1+1+5)+7=891
x8=891-7=884
x=884:8=221/2=110.5
x + x + x + 5 * x + 2 = 891
x * 1 + x * 1 + x * 1 + 5 * x + 2 = 891
x * ( 1 + 1 + 1 + 5 ) = 891 - 2
x * 8 = 889
x =889 :8
x = 111,125
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Tìm x thuộc N biết :
(X-5) mũ 2 =25
(2x+1) mũ 2=25
(3x - 2 mũ 4).7 mũ 3=2.7 mũ 4
2.3 mũ x + 3 mũ 2+x=891
a,(x-5)^2=25
(x-5)^2=5^2
=>x-5=5
x=5+5=10
Vậy x=10
b,(2x+1)^2=25
(2x+1)^2=5^2
=>2x+1=5
2x=6
x=6:2
x=3
Vậy x=3
c,(3x-2^4).7^3=2.7^4
3x-2^4=2.7^4:7^3=14
3x=16+14=30
x=30:3
x=10
Vậy x=10
d,2.3^x+3^2+x=891
tim x (-2/1.3+-2/3.5+...+-2/47.49)-2(x+1)=-3/1.2+-3/2.3+...+-3/48.49
2 x 3 mũ x+ 3 mũ 2 +x = 891
\(2\cdot3^x+3^{2+x}=891\\\Rightarrow 3^x\cdot2+3^x\cdot3^2=891\\\Rightarrow 3^x\cdot(2+3^2)=891\\\Rightarrow 3^x\cdot(2+9)=891\\\Rightarrow 3^x\cdot 11=891\\\Rightarrow 3^x=891:11\\\Rightarrow 3^x=81\\\Rightarrow 3^x=3^4\\\Rightarrow x=4\)
Vậy $x=4$.
\(2\cdot3^x+3^{2+x}=891\)
=>\(2\cdot3^x+3^x\cdot9=891\)
=>\(3^x=\dfrac{891}{11}=81\)
=>x=4
Tim x biet 2.3x+2+3x+1+3x-1=26.92
tim x ,
a, 2^8.4 .x=128,
b, 2.3^8 +3^x-1=63
tim x biet 5^(2x-3)-2.5^2=5^2.3
5^(2x-3) = 5^2.3 + 2.5^2
5^(2x-3) = 5^2( 3 + 2)
5^(2x-3) = 5^2.5
5^(2x-3) = 5^3
2x - 3 =3
2x = 6
x = 3
1:Tim x
( x-3)(x-5)=0
(x+7).35 = 2.35
2 : Tinh tong
1.2+2.3+3.4+....................+99.100
1) (x-3)(x-5) = 0
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x-5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
(x+7).35 = 2.35
\(\Rightarrow x+7=2\)
\(\Rightarrow x=2-7=-5\)
Vậy x = -5
2) 1.2 + 2.3 + 3.4 + .... + 99.100
Đặt A = 1.2 + 2.3 + .... + 99.100
3A = 1.2.3 + 2.3.4 + 3.4.3 + .... + 99.100.3
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2)+ .... + 99.100.(101-98)
3A = ( 1.2.3 + 2.3.4 + 3.4.5 +.... + 99.100.101 ) - ( 0.1.2 + 1.2.3 + 2.3.4 + ... + 98.99.100 )
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A = 999900
A = 999900 : 3
A = 333300
Vậy A = 333300
1
\(\left(x-3\right)\left(x-5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x-5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-3\\x=-5\end{cases}}}\)
\(\left(x+7\right).35=2.35\)
\(x+7=2=>x=-5\)
A=1.2+2.3+3.4...+99.100
=> 3A= 1.2.3+2.3.3+3.4.3...+99.100.3
=> 3A=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+99.100(101=98)
=> 3A= (1.2.3+2.3.4+3.4.5+...+99.100.101)-(0.1.2+1.2.3+..+98.99.200)
=> 3A= 99.100.101-0.1.2
=> 3A= 999900-0=999900
=> A= 999900:3=333300
Tim x
\(2.3^x-405=3^{x-1}\)