a: =>x=1135:37=1135/37

b: =>3x=165

hay x=55

c: =>x-8=92

hay x=100

\(a,x=1135:37=30\left(dư.27\right)\\ b,x\times3=40755:247=165\\ x=165:3=55\\ c,x-8=57316:623=92\\ x=92+8=100\)

Giải cụ thể giúp mình với

\(a,x\times3,14=3,768\)

\(\Leftrightarrow x=3,768:3,14\)

\(\Leftrightarrow x=1,2\)

\(b,\dfrac{2}{3}\times x=\dfrac{1}{4}\)

\(\Leftrightarrow x=\dfrac{1}{4}:\dfrac{2}{3}\)

\(\Leftrightarrow x=\dfrac{1}{4}\times\dfrac{3}{2}\)

\(\Leftrightarrow x=\dfrac{3}{8}\)

a: \(\Leftrightarrow x\cdot12.71=1.269\)

hay x=1269/12710

a: \(\Leftrightarrow x\cdot12.71=1.269\)

hay x=1269/12710

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a) \(A=x^{15}+3x^{14}+5\)

\(=x^{14}\left(x+3\right)+5\)

\(=x^{14}.0+5\)

= 5

b) x = -3 => x + 3 = 0

\(B=\left(x^{2007}+3x^{2006}+1\right)^{2007}\)

\(=\left[x^{2006}\left(x+3\right)+1\right]^{2007}\)

\(=\left(x^{2006}.0+1\right)^{2007}\)

\(=1^{2007}=1\)

\(A=x^{15}+3.x^{14}+5\text{ biết x+3=0}\)

\(A=x^{14}.\left(x+3\right)+5\)

\(\text{Do x+3=0}\Rightarrow A=x^{14}.0+5\)

\(A=0+5\)

\(A=5\)        \(\text{Vậy }A=5\text{ với x+3=0}\)

\(B=\left(x^{2007}+3.x^{2006}+1\right)^{2007}\text{ biết x=-3}\)

\(B=\left[x^{2006}.\left(x+3\right)+1\right]^{2007}\)

\(\text{Do x=-3}\Rightarrow B=\left[x^{2006}.\left(-3+3\right)+1\right]^{2007}\)

\(B=\left(x^{2006}.0+1\right)^{2007}\)

\(B=\left(0+1\right)^{2007}\)

\(B=1^{2007}\)

\(B=1\)           \(\text{Vậy }B=1\text{ với x=-3}\)

Ngu thì câm mồm đi

\(A=x^6-2007x^5+2007x^4-2007x^3+2007x^2-2007x+2007\)

\(=x^6-2006x^5-x^5+2006x^4+x^4-2006x^3-x^3+2006x^2+x^2-2006x-x+2006+1\)

\(=x^5\left(x-2006\right)-x^4\left(x-2006\right)+x^3\left(x-2006\right)-x^2\left(x-2006\right)+x\left(x-2006\right)-\left(x-2006\right)+1\)

\(=\left(x^5-x^4+x^3-x^2+x-1\right)\left(x-2006\right)+1\)

Thay x = 2006

\(\Leftrightarrow A=1\)

Vậy A = 1 tại x = 2006

\(A=x^6-2007.x^5+2007.x^4-2007.x^3+2007.x^2-2007.x+2007\)

\(=x^6-\left(x+1\right).x^5+\left(x+1\right).x^4-...+x+1\)

\(=x^6-x^6-x^5+x^5+x^4-x^4-...-x+1\)

\(=1\)