1. 3x+9.3-x=10
Bài 1 Tính
a, 12/21-3/7+-2/3
b,(-25/13)+(-9/17)+12/13+(-25/17)
c,5/9.7/13+5/9.9/13-5/9.3/13
Bài 2 tìm x
a,2/3x+5/7=3/10
b,x:5/2-1/2=-2/3
c,|x-3/4|-1/2=0
Bài 1 :
a) \(\frac{12}{21}-\frac{3}{7}+\left(-\frac{2}{3}\right)=\frac{4}{7}-\frac{3}{7}+\left(-\frac{2}{3}\right)=\frac{1}{7}-\frac{2}{3}=-\frac{11}{21}\)
b) \(\left(-\frac{25}{13}\right)+\left(-\frac{9}{17}\right)+\frac{12}{13}+\left(-\frac{25}{17}\right)\)
\(=\left[\left(-\frac{25}{13}\right)+\frac{12}{13}\right]+\left[\left(-\frac{9}{17}\right)+\left(-\frac{25}{17}\right)\right]\)
\(=-1+\left(-2\right)=-1-2=-3\)
c) \(\frac{5}{9}\cdot\frac{7}{13}+\frac{5}{9}\cdot\frac{9}{13}-\frac{5}{9}\cdot\frac{3}{13}=\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)=\frac{5}{9}\cdot1=\frac{5}{9}\)
Bài 2 :
a) \(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
=> \(\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}=-\frac{29}{70}\)
=> \(x=\left(-\frac{29}{70}\right):\frac{2}{3}=\left(-\frac{29}{70}\right)\cdot\frac{3}{2}=-\frac{87}{140}\)
b) \(x:\frac{5}{2}-\frac{1}{2}=-\frac{2}{3}\)
=> \(x:\frac{5}{2}=-\frac{2}{3}+\frac{1}{2}=-\frac{1}{6}\)
=> \(x=\left(-\frac{1}{16}\right)\cdot\frac{5}{2}=-\frac{5}{32}\)
c) Bạn chỉ cần xét hai trường hợp âm và dương thôi :>
Tìm x
a) \(2^{3x+2}=4^{x+5}\)
b)\(3^{-1}.3^x+9.3^x=28\)
GIÚP MK NHÉ, MK CẢM ƠN NHIỀU !!!
a) 23x+2 = 4x+5 = (22)x+5 = 22x+10
=> 3x + 2 = 2x + 10
=> 3x - 2x = 10 - 2
x = 8
b) 3-1.3x + 9.3x = 28
3x. ( 3-1 + 9) = 28
3x. 28/3 = 28
3x = 3 = 31
=> x = 1
\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)
\(\Rightarrow3x+2=2\left(x+5\right)\)
\(\Rightarrow3x+2=2x+10\)
\(\Rightarrow3x-2x=10-2\Rightarrow x=8\)
\(3^{-1}.3^x+9.3^x=28\)
\(\Rightarrow\frac{1}{3}.3^x+9.3^x=28\)
\(\Rightarrow3^x.\left(9+\frac{1}{3}\right)=28\)
\(\Rightarrow3^x.\frac{28}{3}=28\)
\(\Rightarrow3^x=3\Rightarrow x=1\)
Chúc bạn học tốt.
\(\frac{2^9.3^{10}+2^8.3^7.135}{2^{10}.3^{10}+2^9.3^{11}}\)
Ta có :
\(\frac{2^9.3^{10}+2^8.3^7.135}{2^{10}.3^{10}+2^9.3^{11}}\)\(=\frac{2^9.3^{10}+2^8.3^7.3^3.5}{2^{10}.3^{10}+2^9.3^{11}}=\frac{2^9.3^{10}+2^8.3^{10}.5}{2^{10}.3^{10}+2^9.3^{11}}=\frac{2^8.3^{10}.\left(2+5\right)}{2^8.3^{10}.\left(2^2+2.3\right)}=\frac{7}{10}\)
Ủng hộ mk nha !!!! ***
\(=\frac{2^9.3^{10}+2^8.3^7.3^3.5}{2^{10}.3^{10}+2^9.3^{11}}=\frac{2^8.3^{10}.\left(2+5\right)}{2^8.3^{10}.\left(2^2+2.3\right)}=\frac{7}{10}\)
15116544
tích mình nhé các bạn thân yêu
8.a2b + c.deb vậy d = ? 2 ; 0 ; 3 ; 1
a.bc x10 = 5.2 x 10 + 9.3 Vậy b = ?
Tim x€n
a.72.2-6.(2x+5)=10^5:10^3
b.(5x+3^4).6^8=6^9.3^4
Tim x€n
a.72.2-6.(2x+5)=10^5:10^3
b.(5x+3^4).6^8=6^9.3^4
9.3^x+1= 81
9.3^x+1= 81
3^2.3^x+1= 81
3^x+3=81
3^x+3=3^4
Suy ra x+3=4
x= 4-3
x=1
\(9.3^{x+1}=81\)
\(\Rightarrow3^{x+1}=81:9\)
\(\Rightarrow3^{x+1}=9\)
\(\Rightarrow3^{x+1}=3^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
10+2x=45:9.3
`10+2x=45:9×3`
`10+2x=5×3`
`10+2x=15`
`2x=15-10`
`2x=5`
`x=5/2`
10+2x=45:9.3
=>10+2x=5.3
=>10+2x=15
=>2x=15-10
=>2x=5
=>x=5:2
=>x=2,5
Vậy x=2,5
tìm x biết 3^x+9.3^x+2-10.3^x+1
2^10.3^10-2^10.3^9/2^9.3^10