\((-15)-[2^4.3+5.(17-25)]\)
thực hiện phép tính
a) 81^11.3^17/27^10.9^15
b) A=2^12.3^5-4^6.9^2/(2^2.3^6)+8^4.3^5-5^10.7^3-25^5.49^2/(125.7)^3+5^9
giúp mình vowisddang cần gấp. cảm ơn
a) 81^11.3^17/27^10.9^15
=(9^2)^11.3^17/(3^3)^10.9^15
=3^44.3^17/3^30.3^30
=3^61/3^60
=3
b) A =( (2^12.3^5 - 2^12.3^4)/ (2^12.3^6 + 2^12.3^5) ) - ((5^10.7^3 - 5^10.7^4)/(5^9.7^3 + 5^9.2^3.7^3))
=(2^12.3^4(3-1))/2^12.3^5(3+1) - 5^10.7^3(1-7)/5^9.7^3(1+8)
=2/12- (-30/9)=1/6 + 10/3 = 7/2
\left(4\dfrac{4}{9} + 5\dfrac{4}{11}\right) -1\dfrac{4}{9} =(494+5114)−194
tính giá trị:
A=\(\frac{5}{6}-\frac{-1}{12}+\frac{2}{3}-\frac{-2}{7}+\frac{1}{25}-\frac{-1}{4}-\frac{5}{42}\)
B=\(\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}2^{26}}\)
Tính:
a) (-5)^60.30^5/15^5.5^61 b) (-3)^10.15^5/25^3.(-9)^7
c)4^6.9^5+6^9.120/8^4.3^12-6^11 d) 4^2.25^2+32.125/2^3.5^2
1) -145.(13 - 57) + 57.(10 -145)
2) 17.(15 - 16) + 16.( 17- 20)
3) -38.(25 - 4) + 25.(-4 + 38 )
4) 23.(145 - 17) - 145.(23 - 6)
5) 24.(15 - 4) + 4.(24 - 15)
6) 199.(15 - 17) - 199.(-17 + 5)
7) -39.(5 - 99) + 99.(10 - 39)
1: \(=-145\cdot13+145\cdot57+57\cdot10-57\cdot145=-1315\)
2: \(=17\cdot15-17\cdot16+16\cdot17-16\cdot20=255-320=-65\)
3: \(=-38\cdot25+38\cdot4-25\cdot4+25\cdot38=13\cdot4=52\)
4: \(=23\cdot145-23\cdot17-145\cdot23+145\cdot6=479\)
5: \(=24\cdot15-24\cdot4+4\cdot24-4\cdot15=360-60=300\)
6: \(=199\left(15-17+17-5\right)=199\cdot10=1990\)
7: \(=-39\cdot5+39\cdot99+99\cdot10-99\cdot39=795\)
1: =−145⋅13+145⋅57+57⋅10−57⋅145=−1315=−145⋅13+145⋅57+57⋅10−57⋅145=−1315
2: =17⋅15−17⋅16+16⋅17−16⋅20=255−320=−65=17⋅15−17⋅16+16⋅17−16⋅20=255−320=−65
3: =−38⋅25+38⋅4−25⋅4+25⋅38=13⋅4=52=−38⋅25+38⋅4−25⋅4+25⋅38=13⋅4=52
4: =23⋅145−23⋅17−145⋅23+145⋅6=479=23⋅145−23⋅17−145⋅23+145⋅6=479
5: =24⋅15−24⋅4+4⋅24−4⋅15=360−60=300=24⋅15−24⋅4+4⋅24−4⋅15=360−60=300
6: =199(15−17+17−5)=199⋅10=1990=199(15−17+17−5)=199⋅10=1990
7: =−39⋅5+39⋅99+99⋅10−99⋅39=795
Tính
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 : 15
15 . 2³ + 4.3² -5.7
5.4² - 18 : 3²
6² : 4.3 + 2.5³
80 - ( 4.5² - 3.2³)
Lời giải:
a.
$=5^{6-3}+2^{3-2}=5^3+2^1=125+2=127$
b.
$=3333:3+225:15=1111+15=1126$
c.
$=15.2^3+4.3^2-5.7=15.8+4.9-35=120+36-35=120+1=121$
d.
$=5.4^2-18:3^2=5.16-18:9=80-2=78$
e.
$=6^2:4.3+2.5^3=36:4.3+2.125$
$=9.3+250=27+250=277$
f.
$=80-(4.25-3.8)=80-(100-24)=80-100+24=-20+24=4$
Tính
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 : 15
15 . 2³ + 4.3² -5.7
5.4² - 18 : 3²
6² : 4.3 + 2.5³
80 - ( 4.5² - 3.2³)
tính giá trị biểu thức sau(tính nhanh nếu có thể)
a)3^3.9-3^4.3+5^8.5^0-5^12:25^2
b)A=(25^6+15^6-10^6):5^6
c)B=9!-8!-7!.8^2
Tính hợp lí
1) -145.(13 - 57) + 57.(10 -145)
2) 17.(15 - 16) + 16.( 17- 20)
3) -38.(25 - 4) + 25.(-4 + 38 )
4) 23.(145 - 17) - 145.(23 - 6)
5) 24.(15 - 4) + 4.(24 - 15)
6) 199.(15 - 17) - 199.(-17 + 5)
7) -39.(5 - 99) + 99.(10 - 39)
tính :
\(A=\dfrac{2^{15}.3^5-4^6.9^2}{\left(2^2.3\right)+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^{3^{ }}}\)
\(A=\dfrac{2^{15}.3^5-4^6.9^2}{\left(2^2.3\right)+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(\Leftrightarrow A=\dfrac{2^{15}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^2.3+\left(2^3\right)^4.3^5}-\dfrac{5^{10}.7^3-\left(5^2\right)^5.\left(7^2\right)^2}{\left(5^3\right)^3.7^3+5^9.14^3}\)
\(\Leftrightarrow A=\dfrac{2^{15}.3^5-2^{12}.3^4}{2^2.3+2^{12}.3^5}-\dfrac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.\left(7.2\right)^3}\)
\(\Leftrightarrow A=\dfrac{2^{12}.3^4\left(2^3.3-1\right)}{2^2.3\left(1+2^{10}.3^4\right)}-\dfrac{5^{10}.7^3\left(1-7\right)}{5^9.7^3\left(1+2^3\right)}\)
\(\Leftrightarrow A=\dfrac{2^{10}.3^3\left(2^3.3-1\right)}{\left(1+2^{10}.3^4\right)}-\dfrac{5\left(1-7\right)}{\left(1+2^3\right)}\)
\(\Leftrightarrow A=\dfrac{1024.9\left(8.3-1\right)}{\left(1+1024.81\right)}-\dfrac{5\left(1-7\right)}{\left(1+8\right)}\)
\(\Leftrightarrow A=\dfrac{9216\left(24-1\right)}{\left(1+82944\right)}-\dfrac{5\left(1-7\right)}{\left(1+8\right)}\)
\(\Leftrightarrow A=\dfrac{9216.23}{82945}-\dfrac{5\left(-6\right)}{9}\)
\(\Leftrightarrow A=\dfrac{211968}{82945}+\dfrac{30}{9}\)
\(\Leftrightarrow A=\dfrac{1907712}{746505}+\dfrac{2488350}{746505}\)
\(\Leftrightarrow A=\dfrac{1907712+2488350}{746505}\)
\(\Leftrightarrow A=\dfrac{4396062}{746505}\)