Tìm X:
\(\frac{12+X}{43-X}\)= \(\frac{2}{3}\).
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\(\frac{12+x}{43-x}=\frac{2}{3}\)
Tìm x là số tự nhiên
12 + x / 43 - x có tổng là 12 + 43 = 55
Tổng số phần bằng nhau :
2 + 3 = 5 ( phần )
Giá trị 1 phần :
55 : 5 = 11
x là :
( 11 x 2 ) - 12 = 10
\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow2\left(43-x\right)=3\left(12+x\right)\)
\(\Leftrightarrow86-2x=36+3x\)
\(\Leftrightarrow86-36=3x+2x\)
\(\Leftrightarrow50=5x\Leftrightarrow x=10\)
tìm số tự nhiên x , biết
a , \(\frac{12+x}{43-x}=\frac{2}{3}\)
b,\(\frac{x}{5}\)nhỏ hơn\(\frac{3}{7}\)
c, 1 nhỏ hơn \(\frac{11}{x}\)nhỏ hơn 2
12 + x / 43 - x có tổng là 12 + 43 = 55
Tổng số phần bằng nhau :
2 + 3 = 5 ( phần )
Giá trị 1 phần :
55 : 5 = 11
x là :
( 11 x 2 ) - 12 = 10
b ) x/5 < 3/7 <=> 7x/35 < 15/35
=> 7x = 14
x = 2
c ) 1 < 11/x < 2
11/5 > 2
=> 5 < x < 11
x { 6 ; 7 ; 8 ; 9 ; 10 }
\(\frac{12+x}{43-x}=\frac{2}{3}\)
VERY GẤP !!!!!!!!!!!
\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Rightarrow\frac{\left(12+x\right)\times3}{\left(43-x\right)\times3}=\frac{2\times\left(43-x\right)}{\left(43-x\right)\times3}\)
\(\Rightarrow\frac{36+3x}{129-3x}=\frac{86-2x}{129-3x}\)
\(\Rightarrow\frac{36+3x}{129-3x}-\frac{86-2x}{129-3x}=0\)
\(\Rightarrow\frac{36+3x-86+2x}{129-3x}\)
\(\Rightarrow\frac{-50+5x}{129-3x}\)
k cho minh
2/3 = 22/33
Vậy x = 22 - 12 = 10
Chúc bạn hok tốt nha!
\(\frac{12+x}{^{43+x}}\)= \(\frac{2}{3}\)
\(\frac{12+50}{43+129}=\frac{2}{3}\)
\(\Rightarrow3\left(12+x\right)=2\left(43+x\right)\)
\(\Leftrightarrow36+3x=86+2x\)
\(\Leftrightarrow x=86-36=50\)
\(\frac{12+x}{43-x}\)= \(\frac{2}{3}\)
\(\frac{12+x}{43-x}=\frac{2}{3}\)
2 ( 43 - x ) = 3 ( 12 + x )
86 - 2x = 36 + 3x
86 - 36 = 3x + 2x
5x = 50
x = 10
Vậy,......
(12 + x) . 3 = (43 - x) . 2
36 + 3x = 86 - 2x
86 - 36 = 3x + 2x
50 = 5x
x = 50 : 5
x = 10
\(\frac{12+x}{43-x}=\frac{2}{3}\)
=> (12 + x)3 = 2(43 - x)
=> 36 + 3x = 86 - 2x
=> 3x + 2x = 86 - 36
=> 5x = 50
=> x = 10
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
Tìm x, biết:
3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)
2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)
x+110 +2+111 x+112 =x+113 +x+114
x−1030 +x−1443 +x−595 +x−1488 =0
Tìm x là số tự nhiên biết :
a) \(\frac{x}{17}=\frac{60}{204}\) b) \(\frac{6+x}{33}=\frac{7}{11}\) c) \(\frac{12+x}{43-x}=\frac{2}{3}\)
d)\(\frac{x}{5}< \frac{3}{7}\) e) \(1< \frac{11}{x}< 2\) g) \(\frac{15}{26}+\frac{x}{16}=\frac{46}{52}\)
HELP ME !
a)\(\frac{x}{17}=\frac{60}{204}=\frac{5}{17}\Rightarrow x=5\)
b)\(\frac{6+x}{33}=\frac{7}{11}\Rightarrow11\left(6+x\right)=7.33\Rightarrow11.6+11x=231\Rightarrow66+11x=231\)
\(\Rightarrow11x=231-66\Rightarrow11x=165\Rightarrow x=\frac{165}{11}=15\)
c)\(\frac{12+x}{43-x}=\frac{2}{3}\Rightarrow2\left(43-x\right)=3\left(12+x\right)\Rightarrow2.43-2x=3.12+3x\)
\(86-2x=36+3x\Rightarrow86-36=3x+2x\Rightarrow50=5x\Rightarrow x=\frac{50}{5}=10\)
Tìm số tự nhiên x sao cho:
\(\frac{12+x}{43-x}=\frac{2}{3}\)
Giúp mk nhé
\(\frac{12+x}{43-x}=\frac{2}{3}\)\(\Rightarrow3\left(12+x\right)=2\left(43-x\right)\)
\(\Rightarrow36+3x=86-2x\)
\(\Rightarrow36+3x-86+2x=0\)
\(\Rightarrow5x=50\)
\(\Rightarrow x=10\)
\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\frac{\left(12+x\right)\times3}{\left(43-x\right)\times3}=\frac{2\times\left(43-x\right)}{3\times\left(43-x\right)}\)
\(\left(12+x\right)\times3=2\times\left(43-x\right)\)
\(36+x\times3=86-2\times x\)
\(x\times3+2\times x=86-36\)
\(x\times5=50\)
\(x=50\div5\)
\(x=10\)
Tìm x là số tự nhiên biết :
A)\(\frac{x}{17}\)= \(\frac{60}{204}\)
B) \(\frac{6+x}{33}\)= \(\frac{7}{11}\)
C)\(\frac{12+x}{43-x}\)= \(\frac{2}{3}\)
A/ \(\frac{x}{17}=\frac{60}{204}\)
\(204x=60.17\)
\(204x=1020\)
\(x=\frac{1020}{204}\)
\(x=\frac{17}{4}=4,25\)
vậy x= 4,25
B/ \(\left(6+x\right).11=33.7\)
\(66+11x=231\)
\(11x=231-66=165\)
\(x=\frac{165}{11}\)
\(x=15\)
vậy x = 15
C/ \(\left(12+x\right).3=\left(43-x\right).2\)
\(36+3x=86-2x\)
\(3x+2x=86-36\)
\(5x=50\)
\(x=\frac{50}{5}=10\)
vậy x=10
mk nhầm
phần a là \(\frac{1020}{204}\)= 5 nha
mk nhầm, xin lỗi