\(=\left(2^5\right)^{60}\)và \(\left(3^4\right)^{50}\)\(=2^{300}< 3^{200}\)

\(=\left(2^5\right)^{60}\)và \(\left(3^4\right)^{50}\)

\(=2^{199}.2^{101}\)và \(3^{199}.3^1\)

\(32^{60}>81^{50}\)

Ta có : 32⁶⁰ = (2⁵)⁶⁰ = 2³⁰⁰ = (2³)¹⁰⁰ = 8¹⁰⁰

            81⁵⁰ = (3⁴)⁵⁰ =3²⁰⁰ = (3²)¹⁰⁰ = 9¹⁰⁰

Mà 8¹⁰⁰ < 9¹⁰⁰

=> 32⁶⁰ < 81⁵⁰

32\(^{^{ }60}\)<81\(^{50}\)

32 mũ 60 > 81 mũ 50

ta có:\(32^{60}=\left(2^5\right)^{^{60}}=2^{5.60}=2^{300}=\left(2^3\right)^{^{100}}=8^{100}\)

và \(81^{50}=\left(3^4\right)^{^{50}}=3^{4.50}=3^{200}=\left(3^2\right)^{^{100}}=9^{100}\)

vì \(8^{100}< 9^{100}\)nên \(32^{60}< 81^{50}\).

so sánh à

ta có 32 mũ 60 bằng 4 mũ 2.5 tất cả 60 bằng 4 mũ 150

         81 mũ 50 bằng 3 mũ 3 tất cả mũ 50 bằng 3 mũ 150

Suy ra 4 mũ 150 lớn hơn 3 mũ 150 hay 32 mũ 60 lớn hơn 81 mũ 50

\(32^{60}=\left(2^5\right)^{60}=2^{300}\) 

\(81^{50}=\left(3^4\right)^{50}=3^{200}\) 

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)  

\(3^{200}=\left(3^2\right)^{100}=9^{100}\) 

\(8< 9\) 

\(\Rightarrow8^{100}< 9^{100}\) 

\(\Rightarrow3^{200}< 2^{300}\)  

\(\Rightarrow32^{60}< 81^{50}\)

a. 5³⁶ và 11²⁴

Ta có : 5³⁶ = ( 5³ )¹² = 125¹²

11²⁴ = ( 11² )¹² = 121¹²

Vì 125¹² > 121¹² 

nên 5³⁶ > 11²⁴

b. 32⁶⁰ và 81⁵⁰

Ta có : 32⁶⁰ = ( 2⁵ )⁶⁰ = 2³⁰⁰ = 8¹⁰⁰

81⁵⁰ = ( 3⁴ )⁵⁰ = 3²⁰⁰ = 9¹⁰⁰

Vì 8¹⁰⁰ < 9¹⁰⁰

nên 32⁶⁰ < 81⁵⁰

hỏi huốn  rose

f: =20:4+5

=5+5

=10

e: =125-100=25

tự tính

Chọn A.

Dựa vào bảng đã cho ta có bảng phân bố tần số; tần suất như sau:

a/

\(27^{81}=\left(3^3\right)^{81}=3^{241}\)

\(81^{27}=\left(3^4\right)^{27}=3^{108}\)

\(\Rightarrow27^{81}=3^{241}>3^{108}=81^{27}\)

b/

\(5^{60}=\left(5^3\right)^{20}=125^{20}\)

\(7^{40}=\left(7^2\right)^{20}=49^{20}\)

\(\Rightarrow5^{60}=125^{20}>49^{20}=7^{40}\)

c/

\(11^{102}=\left(11^2\right)^{51}=121^{51}>121^{50}>99^{50}\)

d. So sánh a=12^34567 với b=(12^5)^12=12^60 => a>b

so sánh b=(12^5)^12 với c=34567^12 => b>c

Vậy a>c.

so sánh b=(12^5)^12=248832^12 với c=34567^12 => b>c

a) (38 - 60) + (20 - 38)

= 38 - 60 + 20 - 38

= (38 - 38) + (-60 + 20)

= 0 - 40

= -40

b) 75 - (20 + 75)

= 75 - 20 - 75

= (75 - 75) - 20

= 0 - 20

= -20

c) 32 + (60 - 32)

= 32 + 60 - 32

= (32 - 32) + 60

= 0 + 60

= 60

d) (81 - 36) - (81 - 36)

= 81 - 36 - 81 + 36

= (81 - 81) + (-36 + 36)

= 0 + 0

= 0

e) (2 + 4 + 6 + 8) - (1 + 3 + 5 + 7)

= 2 + 4 + 6 + 8 - 1 - 3 - 5 - 7

= (2 - 1) + (4 - 3) + (6 - 5) + (8 - 7)

= 1 + 1 + 1 + 1

= 4

f) (1 + 3 + 5 + 7 + ... + 99) - (2 + 4 + 6 + 8 + ... + 100)

= 1 + 3 + 5 + 7 + ... + 99 - 2 - 4 - 6 - 8 - ... - 100

= (1 - 2) + (3 - 4) + (5 - 6) + (7 - 8) + ... + (99 - 100)

= -1 - 1 - 1 - 1 - ... - 1 (50 chữ số 1)

= -50

giúp mình với huhuhuhuhuhu

cảm ơn bạn nhiều !!!!!!!!!✿❤☺

\(a,\dfrac{52}{32}=\dfrac{13}{8}\\ \dfrac{55}{65}=\dfrac{11}{13}\\ MSC:104\\ =>\dfrac{13}{8}=\dfrac{13.13}{8.13}=\dfrac{169}{104}\\ \dfrac{11}{13}=\dfrac{11.8}{13.8}=\dfrac{88}{104}\)

\(b,\dfrac{72}{64}=\dfrac{9}{8}\\ \dfrac{54}{81}=\dfrac{2}{3}\\ MSC:24\\ \dfrac{9}{8}=\dfrac{9.3}{8.3}=\dfrac{27}{24}\\ \dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\\ c,\dfrac{24}{36}=\dfrac{2}{3}\\ \dfrac{12}{30}=\dfrac{2}{5}\\ MSC:15\\ \dfrac{2}{3}=\dfrac{2.5}{3.5}=\dfrac{10}{15}\\ \dfrac{2}{5}=\dfrac{2.3}{3.5}=\dfrac{6}{15}\)

\(d,\dfrac{80}{40}=2\\ \dfrac{45}{63}=\dfrac{5}{7}\\ MSC:7\\ 2=\dfrac{14}{7}\\ e,\dfrac{150}{50}=3\\ \dfrac{100}{200}=\dfrac{1}{2}\\ MSC:2\\ 3=\dfrac{6}{2}\\ f,\dfrac{54}{81}=\dfrac{2}{3}\\ \dfrac{69}{93}=\dfrac{23}{21}\\ MSC:21\\ \dfrac{2}{3}=\dfrac{2.7}{3.7}=\dfrac{14}{21}\)

\(a.\dfrac{52}{32}\text{=}\dfrac{13}{8};\dfrac{55}{65}\text{=}\dfrac{11}{13}\)

\(\dfrac{13.13}{13.8}\text{=}\dfrac{169}{104};\dfrac{11.8}{13.8}\text{=}\dfrac{88}{104}\)

\(c.\dfrac{24}{36}\text{=}\dfrac{2}{3};\dfrac{12}{30}\text{=}\dfrac{2}{5}\)

\(\dfrac{2.5}{3.5}\text{=}\dfrac{10}{15};\dfrac{2.3}{5.3}\text{=}\dfrac{6}{15}\)

\(b.\dfrac{72}{64}\text{=}\dfrac{9.3}{8.3}\text{=}\dfrac{27}{24};\dfrac{54}{81}\text{=}\dfrac{2.8}{3.8}\text{=}\dfrac{16}{24}\)

\(d.\dfrac{80}{40}\text{=}\dfrac{2.63}{63}\text{=}\dfrac{126}{63};\dfrac{45}{63}\)

\(e.\dfrac{150}{50}\text{=}\dfrac{3.2}{2}\text{=}\dfrac{6}{2};\dfrac{100}{200}\text{=}\dfrac{1}{2}\)

\(f.\dfrac{54}{81}\text{=}\dfrac{2.31}{3.31}\text{=}\dfrac{62}{93};\dfrac{69}{93}\)