e ko bt phân tích đa thức thành nhân tử nên a tham khảo linh này nha

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwim29i-oIzyAhVSNKYKHZBdCJ4QFjAAegQIBRAD&url=https%3A%2F%2Fh7.net%2Fhoi-dap%2Ftoan-8%2Fphan-h-da-thuc-5x-2-2x-2-2x-5x-2-6-thanh-nhan-tu-faq341450.html&usg=AOvVaw2Kkix8idzI43uM1i2Mitp4

TL:

(5x^2 - 2x)^2+2x-5x^2-6 

=(\(5x^2\)-2x+3)(\(5x^2\)-2x+2)

các bạn làm giúp mik , mik cần gấp . Làm đc mik chọn cho .

#)Giải :

\(x^3-2x-4\)

\(=x^3+2x^2-2x^2+2x-4x-4\)

\(=x^3+2x^2+2x-2x^2-4x-4\)

\(=x\left(x^2+2x+2\right)-2\left(x^2+2x+2\right)\)

\(=\left(x-2\right)\left(x^2+2x+2\right)\)

\(x^4+2x^3+5x^2+4x-12\)

\(=x^4+x^3+6x^2+x^3+x^2+6x-2x^2-2x-12\)

\(=x^2\left(x^2+x+6\right)+x\left(x^2+x+6\right)-2\left(x^2+x+6\right)\)

\(=\left(x^2+x+6\right)\left(x^2+x-2\right)\)

\(=\left(x^2+x+6\right)\left(x-1\right)\left(x+2\right)\)

Câu 1.

Đoán được nghiệm là 2.Ta giải như sau:

\(x^3-2x-4\)

\(=x^3-2x^2+2x^2-4x+2x-4\)

\(=x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2+2x+2\right)\)

cảm ơn nha!

\(2x^3-x^2+5x+3=2x^3+x^2-2x^2-x+6x+3\)

\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)

\(=\left(2x+1\right)\left(x^2-x+3\right)\)

5 x² - 5xy+2x−2y = 2x ( x - y) + 2( x - y) = 2( x + 1)( x - y)

\(=2x^2-6x+x-3=\left(x-3\right)\left(2x+1\right)\)

\(=2x^2-6x+x-3=2x\left(x-3\right)+\left(x-3\right)=\left(2x+1\right)\left(x-3\right)\)

= 2x^2 - x + 6x - 3

= x(2x - 1) + 3(2x - 1)

= (x + 3)(2x - 1)

\(2x^2+5x-3\)

\(=2x^2+6x-x-3\)

\(=2x\left(x+3\right)-\left(x+3\right)\)

\(=\left(2x-1\right)\left(x+3\right)\)

\(=2x^2+6x-x-3\)

=(x+3)(2x-1)

a) \(=\left(x^2-6\right)\left(x^2-1\right)=\left(x^2-6\right)\left(x-1\right)\left(x+1\right)\)

b) \(=\left(x^2-1\right)\left(x^2+3\right)=\left(x-1\right)\left(x+1\right)\left(x^2+3\right)\)

c) \(=x^2\left(x-1\right)-x\left(x-1\right)+4\left(x-1\right)=\left(x-1\right)\left(x^2-x+4\right)\)

\(-2x^2+5x+3\)

\(=-2x^2+6x-x+3\)

\(=-2x\left(x-3\right)-\left(x-3\right)\)

\(=\left(x-3\right)\left(-2x-1\right)\)

\(=2x\left(x-3y\right)+5\left(x-3y\right)=\left(x-2y\right)\left(2x+5\right)\)

(x−2y)(2x+5)