( 0,25 )⁸ = \(\left(\frac{1}{4}\right)^8=\left(\frac{1}{2^2}\right)^8=\left(\frac{1}{2}\right)^{16}=\left(0,5\right)^{16}\)

( 0,125 )⁴ = \(\frac{1}{8}^4=\left(\frac{1}{2^3}\right)^4=\left(\frac{1}{2}\right)^{12}=\left(0,5\right)^{12}\)

0,25⁸ = (0,5²)⁸ = 0,5¹⁶

0,125⁴ = (0,5³)⁴ = 0,5¹²

_HT_

Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)

0,25⁸=(0,5²)⁸=0,5^2.8=0,5¹⁶

0,125⁴=(0,5³)⁴=0,5^3.4=0,5¹²

Ta có: 

(0,25)^8=((0,5)^2)^8=(0,5)^2.8=(0,5)^16

(0,125)^4=((0,5)^3)^4=(0,5)^3.4=(0,5)^12

cick cho mik nha

0.5 mũ 16 và 0.5 mũ 12

(0,25)^8 = {(0,5)^2}^8 = (0,5)^16 

(0,125)^4 = {(0,5)^3}^4 = (0,5)^12

((0,25)⁸=(0,5²)⁸=(0,5)^2.8=(0,5)¹⁶

((0,125)⁴=(0,5³)⁴=(0,5)^3.4=(0,5)¹²

(0,25)⁸=(0,5²)⁸=(0,5)¹⁶

(0.125)⁸=(0,5³)⁴=(0,5)¹²

\(\begin{array}{l}{\left( {0,25} \right)^8} = {\left[ {{{\left( {0,5} \right)}^2}} \right]^8}=(0,5)^{2.8} = {\left( {0,5} \right)^{16}};\\{\left( {0,125} \right)^4} = {\left[ {{{\left( {0,5} \right)}^3}} \right]^4} =(0,5)^{3.4}= {\left( {0,5} \right)^{12}};\\{\left( {0,0625} \right)^2} = {\left[ {{{\left( {0,5} \right)}^4}} \right]^2} =(0,5)^{4.2}= {\left( {0,5} \right)^8}\end{array}\)